Consider 2 cases:
(1) K >= N
(2) K < N

and fry one side of each steak first.
Try cases like:
N=7,K=1; N=7,K=2; up to N=7,K=6 and find the pattern.

Не совсем понял тестовый пример
3 2
то есть 3 котлеты и можно максимум 2 котлеты жарить в моменте
вначале положим 2 котлеты с одной стороны
потом эти же с другой стороны
потом остается 1 котлета мы ее можем пожарить с одной стороны
это 1 минута и ее же с другой
то есть на нее необходимо 2 минуты

значит всего необходимо 4 минуты
почему ответ 3 ?
как так пожарить

Edited by author 11.06.2023 16:57

Edited by author 11.06.2023 16:57

n = int(input())
k=int(input())
n=n*2
if n % k ==0:
  print(n/k)
else:
    a=int(n/k)+1
    print(a)

I can't find my mistake.
It keep telling me "Runtime error"

n = int(input())
k=int(input())
n=n*2
if n % k ==0:
  print(n/k)
else:
    a=int(n/k)+1
    print(a)

I can't find my mistake.
It keep telling me "Runtime error"

Подскажите, пожалуйста, что не так с кодом? Wrong answer, тест 3.

Edited by author 09.10.2022 19:48

Edited by author 09.10.2022 19:48

a,b=map(int, input().split())
if a==1:
    print(2)
    exit()
if (a*2)//b<a*2/b:
    print(a*2//b+1)
else:
    print(a*2//b)

Почему так не проходит(ошибка на 13):
#include <iostream>
int main() {
    int n,k;
    std::cin>>n>>k;
    if(n<=k) std::cout<<2;
    else std::cout<<n*2/k+n*2%k;

return 0;
}

А так проходит:
    #include <iostream>
int main() {
    int n,k;
    std::cin>>n>>k;
    if(n<=k) std::cout<<2;
    else{
        if(n*2 % k == 0) std::cout<<n*2/k;
        else std::cout<<n*2/k+1;
    }
return 0;
}
Ну или тернар(тоже не проходит - ошибка на 13):
#include <iostream>
int main() {
    int n,k;
    std::cin>>n>>k;
    (n<=k)?std::cout<<2:std::cout<<n*2/k+n*2 % k;

return 0;
}
Может я чего не понимаю, может всё-таки где-то приоритет потерял, но ведь идентично же.

Edited by author 08.10.2021 11:51
Теперь понял, %k может вернуть и больше, чем 1

Edited by author 08.10.2021 12:00

Edited by author 08.10.2021 12:02
C++ ответ:
#include <iostream>
int main() {
    int n,k;
    std::cin>>n>>k;
    (n<=k)?std::cout<<2:(n*2%k==0)?std::cout<<n*2/k:std::cout<<n*2/k+1;

return 0;
}

Edited by author 08.10.2021 12:03

Lets say there are 5 Steaks and capacity of pan is 4.
Step 1: Cook first 4 one side for 1 minute.
Step 2: Replace 1 one sided cooked steak with completely uncooked (remaining) one and
        cook for next 1 minute.
Step 3: Now the chef has 3 completely cooked and 2 Half cooked. Cook the remaining
        2 half cooked for another one minute.

so 1 minute at each step, hence 3 minutes total minimal time.

However, story doesn't end here :-). Lets take another example

Now, Lets say there are 7 Steaks and capacity of pan is 4.
Step 1: Cook first 4 one side for 1 minute.
Step 2: Replace 3 one sided cooked steak with completely uncooked (remaining) three
        and cook for next 1 minute.
Step 3: Now the chef has 1 completely cooked and 6 Half cooked. Cook 4 steaks from
        half cooked six for another one minute.
Step 4: Last cook final 2 half cooked one for another one minute

So total minimum time take is 4 minute. 1 minute at each step.

Please keep in mind the scenarios where 0 steaks or steaks less then cooking capacity of pan.

Edited by author 08.06.2017 20:19

Edited by author 08.06.2017 20:20

import java.io.*;
import java.util.*;

public class task {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        PrintWriter out = new PrintWriter(System.out);
        int n = in.nextInt();
        int k = in.nextInt();
        int t;

        if(n>=1 && k<=1000) {
            if((int) (n * 2.0 / k) == (n * 2.0 / k)) t = (int) (n * 2.0 / k);
            else t = 1 + (int) (n * 2.0 / k);
            out.print(t);

        }
        out.flush();
   }
}

i am doing (n%k)+(n/k) after putting restriction on k(k<=1000) and n(n>=1). but my answer is  said to be wrong.please help.

Edited by author 30.06.2013 01:11

import java.util.Scanner;

public class Zadachi {

    public static void main(String[] args) {

    Scanner sc = new Scanner(System.in);
    int n = sc.nextInt();
    int k = sc.nextInt();
    int x = 2;
        if(n<=k){ System.out.print(x);
        }else{

            if (n*2 % k == 0){
                System.out.print(n*2/k);
            }else{
                System.out.print(n*2/k+1);
            }
        }

}
}

#include "iostream"

using namespace std;
int main()
{
    int a, b, rz;
    cin >> a >> b;
    if (b == 2 && a != 1 || b == 1 && a != 1) {
        rz = 2 * a / b;
    }
    else {
        if (a % b != 0) {
            rz = 2 * (a / b + 1);
        }
        else {
            rz = 2 * a / b;
        }
    }
    cout << rz;
    return 0;
}

i tested it a lot, pleas help may be i am so silly....

public class Pan {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int n = scanner.nextInt();
        int k = scanner.nextInt();

        int m = 2*n;
        if (m%k == 0){
            System.out.println(m/k);
        }
        else{

            System.out.println(m/k+1);
        }
    }
}
why Wrong Answer?

import static java.lang.Math.*;
import java.util.*;

public class UralSteaks {

    public static void main(String[] args) {
        Scanner in=new Scanner(System.in);
        int n,k;
        n=in.nextInt();
        k=in.nextInt();
        int t=(int)ceil(2*(float)n / (float)k);
        System.out.print(t);
    }

}
help plz!

what is 34 test?

New tests have been added to the problem, all accepted solutions have been rejudged. 490 authors have lost their AC.

Компилятор вычисляет все верно, но здесь задача не проходит. Подскажите, знатоки, в чем проблема?

import java.util.Scanner;

public class Main{
    public static void main(String[] args){

        Scanner in = new Scanner(System.in);
        double n = in.nextDouble();
        double k = in.nextDouble();

        if(n>=1&&n<=1000&&k>=1&&k<=1000){
            double a = ((n/k)*2);
            int b = (int)Math.round(a);
            System.out.println(b);
        }
    }
}

import java.io.*;
import java.util.*;

public class t1820 {
    public static void main(String[] args){
        Scanner in = new Scanner(System.in);
        PrintWriter out = new PrintWriter(System.out);
        int n = in.nextInt();
        int k = in.nextInt();
        int rez = 2;

        if (n>k){
            if (n % k == 0) {
                rez = 2*n;
            }
            else{
                if (n % k > k / 2) {
                    rez = (n/k+1)*2;
                }
                else {
                    rez = (n/k-1)*2+3;
                }
            }
        }
        out.println(rez);
        out.flush();
    }
}