Reading the entire input char by char can be done quickly this way:

while ((input = (char)getchar())) {
     if (input == EOF) {
          break;
     }

Check if your input correctly outputs the last word, if the last character is latin.
The first test ends with a .

Edited by author 21.03.2023 18:29

#include <iostream>
#include <vector>
#include <cmath>
#include <string>
#include <stack>
using namespace std;



string solve(string text)
{
    string ts, cs = "", ans = "";
    int i = 0;
    while (i < text.size())
    {

        while(int(text[i]) >= 65 && int(text[i]) <= 122) {
            ts = ""; // create temp string
            ts.push_back(text[i]); // translate char to string
            cs.insert(0, ts); //reverse string
            i++;
        }
        if (i > 0 && int(text[i-1]) >= 65 && int(text[i-1]) <= 122)
        {
            ans += cs; //plus to out ans cypher word
            cs = ""; // make cypher word ""
        }

    ans+=text[i];
    i++;
}
    ans += char(0x20);
    ans += char(0x0a);
    return ans;
}

int main()
{
    string s;
    while(getline(cin, s))
    cout << solve(s);
}

#include <iostream>
#include <string>
#include <algorithm>
using namespace std;
int main() {
    string c = "a";
    string word;
    for (;;) {
        c = getc(stdin);
        if (c[0] == EOF) {
            reverse(word.begin(), word.end());
            cout << word;
            break;
        }
        if (((c[0] >= 'a') && (c[0] <= 'z')) || ((c[0] >= 'A') && (c[0] <= 'Z'))) {
                word.append(c);
        }
        else {
            reverse(word.begin(), word.end());
            cout << word << c;
            word.clear();
        }
    }
}

from sys import stdin
s = ""
for line in stdin:
    for i in line:
        if 'A' <= i <= 'Z' or 'a' <= i <= 'z':
            s += i
        elif 9 < ord(i) < 14 or ord(i) < 0: # <-- this elif about non-printable
            print(s[::-1], end = '\n')      # characters end of lines, files, etc.
            s = ""
        else:
            print(s[::-1] + i, end = '')
            s = ""
print(s, end = '')

I think I can not get AC because of "Enter"  key on Windows  is "\r\n"  and C++ scanf()  reads it as "\n"  and printf()  writes "\n" as "\r\n".
So,  if in input is some "\n",  then I would read it as "\n" and then print it as "\r\n"!!!  I don't know how to fix that.
Also there were problems with EOF-character.

The test is empty. There is nothing there.

I really don't understand why my solution is wrong but here it is:

letters = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
start = 0
s = input()

for i in range(0, len(s)):
    if not(s[i] in letters):
        word = s[start:i]
        other = s[i:i+1]

        if (word != ""):
            print(word[::-1], end="")

        print(other, end="")
        start = i+1

if (start != len(s)):
    print(s[start:len(s)][::-1], end="")

What's wrong with this solution?
WA (Test 2)

Edited by author 30.03.2013 23:10

For those looking for a hint: I use stack.
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Push the characters into stack, when a non-alphabetic character is read, pop out all the characters in stack and print them before printing the non-alphabetic character.

Edited by author 02.10.2018 15:04

#include <bits/stdc++.h>
using namespace std;

#define re return
#define pb push_back
#define all(x) (x).begin(), (x).end()
#define fi first
#define se second
#define sqrt(x) sqrt(abs(x))
#define mp make_pair
#define pi (3.14159265358979323846264338327950288419716939937510)
#define fo(i, n) for(int i = 0; i < n; ++i)
#define ro(i, n) for(int i = n - 1; i >= 0; --i)
#define unique(v) v.resize(unique(all(v)) - v.begin())

template <class T> T abs (T x) { re x > 0 ? x : -x; }
template <class T> T sqr (T x) { re x * x; }
template <class T> T gcd (T a, T b) { re a ? gcd (b % a, a) : b; }
template <class T> int sgn (T x) { re x > 0 ? 1 : (x < 0 ? -1 : 0); }


typedef vector<int> vi;
typedef vector<vi> vvi;
typedef pair<int, int> ii;
typedef vector<ii> vii;
typedef vector<string> vs;
typedef double D;
typedef long double ld;
typedef long long ll;
typedef pair<ll, ll> pll;
typedef vector<ll> vll;
typedef unsigned long long ull;

vi l, r;

int main() {
    //freopen("input.txt", "r", stdin);
    string str;
    while (getline(cin, str)) {
        l.clear(), r.clear();
        if (isalpha(str[0])) l.pb(0);
        fo(i, (int)str.size() - 1) {
            if (!isalpha(str[i]) && isalpha(str[i + 1])) l.pb(i + 1);
            if (isalpha(str[i]) && !isalpha(str[i + 1])) r.pb(i + 1);
        }
        if (isalpha(str.back())) r.pb(str.size());
        fo(i, l.size()) reverse(str.begin() + l[i], str.begin() + r[i]);
        cout << str << '\n';
        str.clear();
    }
}

Here is my code which has been written in java. Please help me. I cannot understand what wrong is. Or some tests you have ?. Thanks.

public class EsreveRredrO_1226 {
    public static void main(String[] args) throws IOException {
        BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
        String s = reader.readLine();
        solve(s);
    }

    public static void solve(String s) {
        String text[];
        text = s.split(" ");
        for (int i = 0; i < text.length; i++) {
            String revers = "";
            String temp;
            for (int j = text[i].length() - 1; j >= 0;  j--) {
                    revers = revers.concat(String.valueOf(text[i].charAt(j)));
            }
            if (revers.charAt(0) == '!' || revers.charAt(0) == ',' || revers.charAt(0) == '.' || revers.charAt(0) == '?'
                    || revers.charAt(0) == ':' || revers.charAt(0) == ' ') {
                temp = revers.substring(1, revers.length());
                revers = temp.concat(String.valueOf(revers.charAt(0)));
            }
            if (i != text.length - 1)
            System.out.print(revers + " ");
            else System.out.print(revers);
        }
    }
}

Edited by author 04.09.2017 00:45

#include <iostream>
#include <iomanip>
#include <map>
#include <vector>
#include <cmath>
#include <vector>
#include <algorithm>
#include <cmath>

using namespace std;

int letter(char c)
{
    return (('a'<=c&&c<='z')||('A'<=c&&c<='Z'));
}

int main()
{
    //freopen("a","r",stdin);
    string s;
    while(getline(cin,s))
    {
        vector<int> l,r;
        for (size_t i=0;i<s.length();i++)
        {
            if (letter(s[i]))
            {
                if (!i||!letter(s[i-1]))
                {
                    l.push_back(i);
                }
                if (i+1==s.length()||!letter(s[i+1]))
                {
                    r.push_back(i+1);
                }
            }
        }
        for (int i=0;i<l.size();i++)
        {
            reverse(s.begin()+l[i],s.begin()+r[i]);
        }
        cout << s << endl;
    }
    return 0;
}

import sys

def reverse(i):
    if len(i) == 1:
        return i
    else:
        return i[len(i)-1]+reverse(i[:len(i)-1])

def getReverseLine(s):
    start = 0
    for i in range(len(s)):
        if (ord(s[i]) < 123 and ord(s[i]) > 64) and (ord(s[i]) < 91 or ord(s[i]) > 96):
            if i == len(s)-1:
                if start < i:
                    s = s.replace(s[start:i+1], reverse(s[start:i+1]))
        else:
            if start < i:
                s = s.replace(s[start:i], reverse(s[start:i]))
                start = i+1
            else:
                start += 1
    return s

lines = []
while True:
    line = sys.stdin.read()
    if line == '':
        break
    lines.append(getReverseLine(line))

text = '\n'.join(lines)

print text

#include <bits/stdc++.h>

using namespace std;
string a,b;
string re(long long c, long long d,string x){
    string y="";
    for(long long i=d; i>=c; i--) y=y+x[i];
    return y;
}
string re2(string x){
    long long t=0;
    string res="";
    for(long long i=0; i<x.size(); i++){
        int q=(int)x[i];
        if(q<65||(q>90&&q<97)||q>122){
            res=res+re(t,i-1,x);
            res=res+x[i];
            t=i+1;
        }
    }
    res=res+re(t,x.size()-1,x);
    return res;
}
int main()
{
    while(getline(cin,a)){
        istringstream iss;
        iss.clear();
        iss.str(a);
        while(iss>>b) cout<<re2(b)<<" ";
        cout<<endl;
    }
}

python 3

my code :

import sys
for t in sys.stdin :
        s = ''
        for i in range(len(t)):
                if (ord(t[i]) >=97 and ord(t[i]) <= 122) or (ord(t[i])>=65 and ord(t[i])<=90):
                        s += t[i]
                else :
                        if len(s) > 0 :
                                print(s[len(s)-1:0:-1]+s[0], end='')
                                s = ''
                        print(t[i], end='')
        print(s, end='')


Edited by author 29.08.2016 01:57

All symbols are important, not "only printable". Pay attention to EOL, EOF, and symbols with codes below 32.

here is my code:
I don't know wht's the error ,anyone help me?

Const
  u=['a'..'z']+['A'..'Z'];
Var
  s:string;
  ch:char;
  i:integer;

Begin
  read(ch);
  while not eof do
     begin
       s:='';
       while (ch in u) and (ord(ch)<>26) do
         begin
           s:=s+ch;
           read(ch);
         end;
       for i:=length(s) downto 1 do write(s[i]);
       while (not (ch in u)) and (ord(ch)<>26) do
         begin
           write(ch);
           read(ch);
         end;
    end;
End.

#include<iostream>
#include<algorithm>
#include<string>
using namespace std;
int main()
{
  string text;
  while(getline(cin,text))
  {
      string s="";
      for(int i=0;i<text.size();i++)
      if(('a'<=text[i]&&text[i]<='z')
||('A'<=text[i]&&text[i]<='Z'))

      s.push_back(text[i]);
      else
      {
          reverse(s.begin(),s.end());
          cout<<s;
          s="";
          cout<<text[i];
          }
          cout<<endl;

          }


            //system("pause");
            return 0;
            }

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.io.PrintWriter;

public class T1226_esreveR_redrO {

    public static void main(String[] args) throws NumberFormatException, IOException {
        BufferedReader reader = new BufferedReader(new InputStreamReader(System.in, "ISO-8859-1"));
        PrintWriter writer = new PrintWriter(new OutputStreamWriter(System.out, "ISO-8859-1"));
        String line = "";
        while ((line = reader.readLine()) != null) {
            String[] lineSplit = line.split(" ");
            reverse(lineSplit);
            String lineReversed = "";
            for (int i = 0; i < lineSplit.length - 1; i++) {
                lineReversed = lineReversed + lineSplit[i] + " ";
            }
            lineReversed = lineReversed + lineSplit[lineSplit.length - 1];
            writer.println(lineReversed);
        }
        writer.flush();

    }

    private static void reverse(String[] lineSplit) {
        for (int i = 0; i < lineSplit.length; i++) {
            String head = "";
            String tail = "";
            String word = lineSplit[i];
            if (!Character.isLetter(word.charAt(0))) {
                head = word.charAt(0) + "";
                word = word.substring(1, word.length());
            }
            if (!Character.isLetter(word.charAt(word.length() - 1))) {
                tail = word.charAt(word.length() - 1) + "";
                word = word.substring(0, word.length() - 1);
            }
            StringBuffer sb = new StringBuffer(word);
            sb = sb.reverse();
            word = head + sb.toString() + tail;
            lineSplit[i] = word;
        }
    }

}

The output text must be exactly as it was given, without any additional new lines (but with all new lines that were in input data).