Damn, how is this problem 440 difficulty, I solved it in 10 minutes

SOLVED

Edited by author 17.10.2017 00:37

Because the input info states that "The single line of the input contains a sequence" ...
The "Single" line
but I got #1WA

here's my code:
#include<stdio.h>
char str[10005],output[85],temp;
int i,ptr;
main()
{
      /*
      while (scanf("%c",&temp)!=EOF)
      {
            if (temp >= 32)
               str[i++]=temp;
      }
      */
      gets(str);

      for (i=0;str[i];i++)
      {
          if (str[i]=='>')
          {
             if (output[ptr]!=0)
             {
                ptr++;
                if (ptr==80)
                   ptr=0;
             }
          }

          else if (str[i]=='<')
          {
               if (ptr>0)
                  ptr--;
          }

          else
          {
              output[ptr]=str[i];
              ptr++;

              if (ptr==80)
                 ptr=0;
          }

      }
      printf("%s",output);
      scanf(" ");
}

Where is my mistake?
Thanks :)

[code][/code] Accepted.I want know the AC solution that has 0.001 time

Edited by author 21.03.2012 22:51

If you read input char-by-char, you should skip "\r" too, not only "\n".

test

a>s

output:
a s

help me!please

#include<stdio.h>
#include<iostream>
using namespace std;

char s[10001],str[80];
int main()
{

#ifndef ONLINE_JUDGE
   freopen("input.txt", "rt", stdin);
   freopen("output.txt", "wt", stdout);
#endif

         int j = 0;
         memset(s,'\0',sizeof(s));
        while(gets(s))
        {
                int len = strlen(s);
                int i = 0;
                while(i<len)
                {
                        if(s[i]=='>')
                        {
                                j++;
                                if(j>79)j=0;
                        }
                        else if(s[i]=='<')
                        {
                                j--;
                                if(j<=0)j=0;
                        }
                        else if(s[i]!='\n' && s[i]!='\0')
                        {
                                str[j] = s[i];
                                j++;
                        }
                        i++;
                }

                memset(s,'\0',sizeof(s));
        }
for(int i = 0;i<80;i++)
printf("%c",str[i]);

return 0;
}

var
 s:array[1..100010] of char;
 i,j,k,l,now,lo:longint;
 a,t1,t2:string;
begin
 a:='';
 for i:=1 to 80 do a:=a+' ';
 i:=0;
 while not(eof) do begin inc(i);read(s[i]); end;
 lo:=i;
 now:=1;
 for i:=1 to lo do
  begin
   if (s[i]='<') then  begin dec(now); if (now=0) then now:=1; continue; end;
   if (s[i]='>') then  begin inc(now); if (now=81) then now:=1; continue; end;
   if now=1 then t1:='' else t1:=copy(a,1,now-1);
   if now=80 then t2:='' else t2:=copy(a,now+1,80-now-1);
   a:=''; a:=t1+s[i]+t2;
   t1:=''; t2:='';
   inc(now); if (now=81)then now:=1;
  end;
  for i:=1 to 80 do write(a[i]);
end.

wrong on the following  code
///////////////////////
if(pos >maxline -1)
  pos = 0;
  a[pos++] = char;
////////////////////
when test case:
aaaaaaaaaaa.......a(total 80 a)<b
b should in pos 1 instead of erasing pos 80

Remember, that in input there are "end-of-line characters".
And you must read string lines until your find "end-of-file characters".
If Java
while (in.hasNextLine()) {
   char input[] = in.nextLine().toCharArray();
      /* analyse-code
      */
}
This method (while(in.hasNext***()) often use, when you don't know the number of input data or you can find "end-of-line characters" in text line.


Edited by author 30.04.2009 18:26

A very easy problem. Just read teh description carefully, there are some traps inside.

Here are a few typical mistakes:

a) you forgot to fill the array with ' '
b) you're doing gets( buff ), and the size of buff is less than 10000
c) you're doing printf( "%s", out ), and you forgot to do out[80] = '\0'
d) if the position becomes 80, you go to 79 instead of 0
e) you don't print trailing spaces

Good luck!

1) For those who get WA 1 mb helps :
with
while (!cin.eof()) char c = cin.get();
i had WA 1
with
char t[10000];
cin.getline(t, 1000);
i had WA 9 !

2)
the problem says that the length of input is no more than 10000 characters

but this code
...
char t[10000];
cin.getline(t, 10000)
...
get WA9
this :
char t[20000];
cin.getline(t, 20000);
get AC

Strange, isn't it?

in example writen---
"Look for second hamburger at computer and chairs.790 "
there mustn't writen "790".
number of "<" is bigger than answer.
and why "790" in the end of sentence!!
pls, explain it to me!!!
thx!!!

and i think it is right!!
program Project1094;

{$APPTYPE CONSOLE}

uses
  SysUtils;

   var
    a : string[80];
    i, j : integer;
    ch : char;
    f, f1 : textfile;

begin
   assign(f, '1094.in');
   assign(f1, '1094.out');
   reset(f);
   rewrite(f1);
   i := 0;
   fillchar(a, sizeOf(a), 0);
   while not eof do
     begin
       read(ch);
       if ch = '>' then  begin
       if i < 80 then begin  inc(i);  a[i] := ' ';  end
       else i := 0;   end;

       if (ch = '<') and (i > 0) then dec(i);
       if (ch <> '<') and (ch <> '>') then  begin  inc(i);  a[i] := ch;  end;
     end;
     for j := 1 to i do
     write(a[j]);
   close(f);
   close(f1);

end.

Edited by author 20.02.2008 23:05

I don't understand task.Please write me explanation on serchch@mail.ru(on russian),if you can.Thank you very much!!!

The first one got AC but the second one got WA.
I have initialized every char in ans to be ' '.

OH, I see...
I should let ans[80] to be '\0'...
sorry..~

Edited by author 23.07.2007 21:58

Why i get Time Limit on test#1 with time 0.001 ??

I didn't understand the question!!! exactly what must our output 123<-456<-7890 <<<<<<<<<<<<<<<<to order <<<<<<<<<<<<<<<<<computers and ...