please answer to me.

var
 k,n,m: Real;
 koren, p: Real;
 ok: Boolean;
begin
 Readln(n);
 k:=0;
 p:=0;
 repeat
 ok:=false;
 m:=n+p;
 koren := (-1+sqrt(1+8*m))/2;
 if frac(koren) < 1e-18 then
  begin
   writeln(round(k+1),' ',round(koren - k));
   ok:=true;
  end
 else
  begin
   k := k + 1;
   p:= (sqr(k) + k)/2;
  end;
 Until ok;
End.

i don`t understant what means "N = A + (A + 1) + … + (A + P − 1)."?

 i think: when A=2:  14=2+(2+1)+(2+2)+(2+3)    P=?

why was p=4 in the subject?



please help me!!!

#include <iostream>
using namespace std;

int main()
{long int N=0,s=0;
 int a=0,p=0,kol=0,z=0;
 cin>>N;
 for (long int i=1;i<=N;i++)
  {s=s+i-1; if (s>N) break;
          else {if ((N-s)%i==0) {a=(N-s)/i;p=i;}}}
   cout<<a<<" "<<p;
  }

WA on 5 test :(
#include <stdlib.h>
#include <string.h>
#include <math.h>

int main()
{
long n,i,a,n0;
double fa;

scanf ("%lli", &n);
for (i=3*sqrt(n); i>0; i--)
{
    fa=(n)/(double)i - ((double)i-1)/2.0;
    a=fa;
    /*printf("fa=%f a=%li p=%li\n",fa,a,i);*/
    n0=((2*a+i-1)*i )/2;
    if (n0==n && a>0) {printf("%li %li\n", a, i); return 0;}
}
printf ("%li 1\n",n);
return 0;
}

if n=1 the answer a=0 p=2 is wrong!
The correct answer is a=1 p=1

You can prove it with the knowledge of maths.

Edited by author 22.08.2007 14:43

Please explain me what the number 316227 means
in the solution of this problem and in the programming at large.Thank you in advance.

Edited by author 04.05.2007 14:55

[code deleted]

please,help me!!!i<=?please,answer!Thank you very much!!!!

Edited by author 27.04.2007 19:53

Edited by moderator 09.05.2007 16:04

Edited by author 09.05.2007 21:59

my code!
please help!
thanks!

#include<stdio.h>
#include<math.h>

long i, j, n, div, p, a;

int main()
{
    scanf("%ld", &n);

    for(i = sqrt(n); i >= 1; i--)
        if(n % i == 0)
        {
            p = i * 2;
            a = n / (p / 2) - (p - 1);
            if(a % 2 == 0 && a / 2 >= 0)
            {
                a = a / 2;
                i = 0;
            }
        }

    printf("%ld %ld\n", a, p);

    return 0;
}

Edited by author 20.04.2007 13:25

Edited by author 20.04.2007 13:25

somebody can help me? or give me more tests.
WA test 8.

  If n=1, a=1 and p=1(1+0)
  If n=3, a=1 and p=2(1+(1+1))
But if n=2? What should I output in this case?
Thanks.

[code deleted]

Edited by moderator 28.07.2006 10:35

What's wrong?
I think, that my program is right:

[code deleted]

Edited by moderator 28.07.2006 10:35

test #9 help,help please
anybody please give me test #9
{================================}

var q1,q,k,p,y,z:real;
n,i:longint;
begin
read(n);
q:=0;
q1:=0;

for i:=round(sqrt(n)*1.2353) downto 1 do
begin
y:=n/i; k:=n/(i+0.5);
 if (frac(y)=0) and (frac(y/2-0.5)=0) and   ((n/y+0.5-y/2)>0) then if q<y then  q:=y;
 if (frac(k)=0) and (frac(k/2)=0)  and  ((n/k+0.5-k/2)>0) then   if q1<k then  q1:=k;
end;

if (q>q1)  then  if (q*q+(2*(n/q+0.5-q/2)-1)*q=2*n) then begin writeln((n/q+0.5-q/2):0:0,' ',q:0:0);z:=1;end;
if (q<q1)  then if (q1*q1+(2*(n/q1+0.5-q1/2)-1)*q1=2*n) then begin writeln((n/q1+0.5-q1/2):0:0,' ',q1:0:0);z:=1;end;
if z<>1 then writeln(n,' ',1);
end.

Edited by author 04.01.2006 17:30

The solution for the input "7" is whether "3 2" or not

plz check my program...

#include<stdio.h>
#include<math.h>

int main()
{
    long n,a,p,x,chk=0,sum=0;
    scanf("%ld",&n);
    for(x=sqrt(n);chk==0;x++)
    {
        if(x*(x+1)/2>n)
        {
            break;
        }
    }
    for(chk=0;x<=n/2+1;x++)
    {
        for(p=1;sum<n;p++)
        {
            sum+=x+1-p;
            if(sum==n)
            {
                a=x+1-p;
                x=n/2+2;
                chk=1;
                break;
            }
        }
        sum=0;
    }
    if(chk==1) printf("%ld %ld",a,p);
    return 0;
}