#include <stdio.h>
#include <math.h>
#include <iostream>
#include <string>
using namespace std;
int main(){
    int n, l = 0;
    string s[10], t[10], r[10];
    scanf("%d", &n);
    s[0] = "Alice";
    s[1] = "Ariel";
    s[2] = "Aurora";
    s[3] = "Phil";
    s[4] = "Peter";
    s[5] = "Olaf";
    s[6] = "Phoebus";
    s[7] = "Ralph";
    s[8] = "Robin";

    t[0] = "Bambi";
    t[1] = "Belle";
    t[2] = "Bolt";
    t[3] = "Mulan";
    t[4] = "Mowgli";
    t[5] = "Mickey";
    t[6] = "Silver";
    t[7] = "Simba";
    t[8] = "Stitch";

    r[0] = "Dumbo";
    r[1] = "Genie";
    r[2] = "Jiminy";
    r[3] = "Kuzko";
    r[4] = "Kida";
    r[5] = "Kenai";
    r[6] = "Tarzan";
    r[7] = "Tiana";
    r[8] = "Winnie";
    string q[10010];
    for(int i = 0; i <= n; i ++){
        getline(cin, q[i]);
    }
    __int64 k[10010], len = 1, sum = 0;
    for(int i = 2; i <= n; i ++){
            int kk = 0;
        for(int j = 0; j < 9 ; j ++){
            if(q[i] == s[j]){
                kk = 1;
            }
            if(q[i] == t[j]){
                kk = 2;
            }
            if(q[i] == r[j]){
                kk = 3;
            }

        }
        k[len] = kk;
    len ++;
    }
k [0] = 1;
    for(int i = 1; i < len; i ++){


        sum += fabs(k[i] - k[i + 1]);

   }
      cout << sum << endl;
}

can someone help me?, im trying search the error but i dont found nothing, greetings..

import java.io.PrintWriter;
import java.util.Scanner;

public class P{

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
    PrintWriter out= new PrintWriter(System.out);
        int current=1,cont=0;

    int n=in.nextInt();
        in.nextLine();
        for(int i=0;i<n;i++){
            String lec;
            lec=in.nextLine();

            if(lec.equals("Aurora") || lec.equals("Alice") ||lec.equals("Ariel") ||lec.equals("Phil")||lec.equals("Peter")||lec.equals("Olaf")||lec.equals("Phoebus")||lec.equals("Ralph")||lec.equals("Robin") ){
                    if(current==2){
                        cont=cont+1;
                    }
                    if(current==3){
                        cont=cont+2;
                    }
                    current=1;
            }
            if(lec.equals("Bambi") || lec.equals("Belle") ||lec.equals("Bolt") ||lec.equals("Mulan")||lec.equals("Mowglin")||lec.equals("Mickey")||lec.equals("Silver")||lec.equals("Simba")||lec.equals("Stitch")){
                    if(current!=2){
                        cont=cont+1;
                    }
                    current=2;
            }
            if(lec.equals("Dumbo") || lec.equals("Genie") ||lec.equals("Jiminy") ||lec.equals("Kuzko")||lec.equals("Kida")||lec.equals("Kenai")||lec.equals("Tarzan")||lec.equals("Tiana")||lec.equals("Winnie")){
                   if(current==2){
                       cont=cont+1;
                   }
                   if(current==1){
                       cont=cont+2;
                   }
                   current=3;
            }
        }

        System.out.print(cont);

    out.flush();
    }
}

#include <iostream>

using namespace std;

int main()
{
    char first[4] = { 'A', 'P', 'O', 'R' };
    char second[3] = { 'B', 'M', 'S'};
    int mail = 0;
    bool  AF=false;//already find
    char *input=new char[200];
    int steps=0,duck=1;
    cin >> mail;
    for (int i = 0; i < mail; i++)
    {
        cin >> input;
        for (int j = 0; j < 4;j++)
        {
            if (input[0] == first[j]&&!AF)
            {
                AF = true;
                if (duck == 1)break;
                if (duck == 2)steps++;
                if (duck == 3)steps += 2;
                duck = 1;
                break;
            }
        }
        if (!AF){
            for (int j = 0; j < 3; j++)
            {
                if (input[0] == second[j] && !AF)
                {
                    AF = true;
                    if (duck == 2)break;
                    else steps++;
                    duck = 2;
                    break;
                }
            }
        }
        if (!AF)
        {
            AF = true;
            if (duck == 3)break;
            if (duck == 2)steps++;
            if (duck == 1)steps += 2;
            duck = 3;
        }
            AF = false;

    }
    cout << steps;
    return 0;
}

Edited by author 17.11.2015 11:26
I found a solution to my problem was laziness. When I described the search for the third block - the answer was accepted as correct. Apparently in the verification test on the 8th provide those names are not on the shelves.

Edited by author 17.11.2015 11:35

What's wrong? Here is my code:

var a,b,c:array [1..3,1..3] of string; d,s,i,j,j1,n,p:longint; x:string;
begin
a[1,1]:='Alice';
a[1,2]:='Ariel';
a[1,3]:='Aurora';
a[2,1]:='Phil';
a[2,2]:='Peter';
a[2,3]:='Olaf';
a[3,1]:='Phoebus';
a[3,2]:='Ralph';
a[3,3]:='Robin';
b[1,1]:='Bambi';
b[1,2]:='Belle';
b[1,3]:='Bolt';
b[2,1]:='Mulan';
b[2,2]:='Mowgli';
b[2,3]:='Mickey';
b[3,1]:='Silver';
b[3,2]:='Simba';
b[3,3]:='Stitch';
c[1,1]:='Dumbo';
c[1,2]:='Genie';
c[1,3]:='Jiminy';
c[2,1]:='Kuzko';
c[2,2]:='Kida';
c[2,3]:='Kenai';
c[3,1]:='Tarzan';
c[3,2]:='Tiana';
c[3,3]:='Winnic';
readln (n);
s:=0;
p:=1;
for i:=1 to n do begin
readln (x);
for j:=1 to 3 do
for j1:=1 to 3 do begin
If x=a[j,j1] then d:=1;
If x=b[j,j1] then d:=2;
If x=c[j,j1] then d:=3;
end;
s:=s+abs (p-d);
p:=d;
end;
writeln (s);
end.

when i try different inputs my code seems to work fine,but i am stuck at test case #5,can anyone please post it?

use simple algorithm:
 - checks only initial.
 - keep state of previous
 - initial state of previous is 1, since postman is in leftmost case

useful test cases:

----
1
Bambi

1 (not 0, because he moves to second case with one step)
----
1
Alice

0
----
1 Dumbo

2
---

#include <iostream>
#include <string>
using namespace std;
int main()
{
    int a[1000];
    int n,i,k;
    char Name;
    cin>>n;
    string B;
    k=0;
    for (i=0;i<n;i++){
        cin>>B;
        Name=B[0];
            if(Name=='A' or Name=='P' or Name=='O' or Name=='R') {a[i]=1;}
            else {if(Name=='B' or Name=='M' or Name=='S') {a[i]=2;}
                else {a[i]=3;};
                }
        }
    k=a[0]-1;

    for (i=1;i<n;i++){
        if (a[i-i]<a[i]){ k=k+a[i]-a[i-1];}
        else { k=k+a[i-1]-a[i];}

        }
    cout<<k;
        return 0;

}

Here is the code(c++), what is wrong?

#include <iostream>
#include <string>
using namespace std;
int main()
{
    string name[1001];
    int counter=0;
    int n,i=0;
    cin>>n;
    while(i<=n)
    {
        getline(cin,name[i]);
        if(i!=0)
            if(name[i-1][0]!=name[i][0])
                if(name[i-1][0] == 'A' || name[i-1][0] == 'P'||name[i-1][0] == 'O'||name[i-1][0] == 'R')
                {
                    if(name[i][0] == 'B' || name[i][0] == 'M'||name[i][0] == 'S')
                        counter++;
                    else
                        counter+=2;
                }
                else if(name[i-1][0] == 'B' || name[i-1][0] == 'M'||name[i-1][0] == 'S')
                {
                    counter++;
                }
                else if(name[i-1][0] == 'D' || name[i-1][0] == 'G'||name[i-1][0] == 'J'||name[i-1][0] == 'K'||name[i-1][0] == 'T'||name[i-1][0] == 'W')
                {
                    if(name[i][0] == 'B' || name[i][0] == 'M'||name[i][0] == 'S')
                        counter++;
                    else
                        counter+=2;
                }
        i++;
    }
    cout<<counter;
}

Can someone give me test cases? I believe my solution works and tried with many possible inputs and I get the right result. I found that it is possible to have more than one input value on the same line. And now I fail to pass #5.

Any test cases would be much appreciated.


Edited by author 20.12.2014 13:42

Подскажите какие могут быть ошибки
Please help me
Edited by author 26.11.2014 19:59

Edited by author 26.11.2014 19:59

Edited by author 13.01.2015 16:12

names = ['Alice', 'Ariel', 'Aurora', 'Phil', 'Peter', 'Olaf', 'Phoebus', 'Ralph', 'Robin',
        'Bambi', 'Belle', 'Bolt', 'Mulan', 'Mowgli', 'Mickey', 'Silver', 'Simba', 'Stitch',
        'Dumbo', 'Genie', 'Jiminy', 'Kuzko', 'Kida', 'Kenai', 'Tarzan', 'Tiana', 'Winnie']

n = int(raw_input())

letters = ['Alice']
for i in range(0, n):
    letters.append(raw_input())

result = 0
for i in range(1, n+1):
    result += int(abs(names.index(letters[i]) - names.index(letters[i -1]))/9)


print result