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вернуться в форумWho can help me?I use graph and search from the end,but WA. Послано kkkkk 30 июл 2004 19:59 const letter:set of char=['a'..'z']; max=100000; var n,t,l,e:longint; c:char; q,start:boolean; s:string; sz:array[1..max]of 0..4;{0:space;1:on;2:put;3:out;4:in} begin readln(n); for t:=1 to n do begin fillchar(sz,sizeof(sz),0); q:=true; start:=true; l:=0; s:=''; e:=0; while not eoln do begin read(c); if c in letter then begin start:=false; s:=s+c; inc(l); if l>=6 then begin q:=false; break; end; if s='e' then begin if sz[e]=1 then begin l:=0; s:=''; sz[e]:=0; dec(e); end else begin q:=false; break; end; end else if (l=2)or(l=3) then begin if s='on' then begin l:=0; s:=''; inc(e); sz[e]:=1; end else if s='put' then begin l:=0; s:=''; inc(e); sz[e]:=2; end else if s='out' then begin l:=0; s:=''; inc(e); sz[e]:=3; end else if s='in' then begin l:=0; s:=''; inc(e); sz[e]:=4; end; end; end else if not start then begin q:=false; break; end; end; if l<>0 then q:=false; l:=e; if q then while l>0 do begin if (sz[l]=4)or(sz[l]=3) then begin l:=l-1; end else if sz[l]=2 then begin if (sz[l-1]=4)or(sz[l-1]=3) then l:=l-2 else begin q:=false; break; end; end else if sz[l]=1 then begin if sz[l-1]=2 then l:=l-2 else begin q:=false; break; end; end; end; readln; if q then writeln('YES') else writeln('NO'); end; end. |
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