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back to boardShow all messages Hide all messages Edited by author 08.09.2004 19:43 I don't think so. T ~ V^2, assuming that gives ac hmm... i think the same. In each jump energy decreases K times, then (E = mv^2/2) speed decreases sqrt(k) times. But my solution, which assuming that speed descreases k times (not sqrt(k)), got AC... Strange Sorry for my poor English=) No,you are wrong,it's correct. Each time v decreases in sqrt(k) times,but we use Vx*Vy,so it decreases in k times. I agree with you kinetic engergy decreases in K times speed decreases in sqrt(K) times Because E=1/2*m*v^2 Edited by author 05.12.2008 16:28 |
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