|
|
вернуться в форумWhy 2*Pi*R ? I solve that problem but I don't understand why I should take 2*Pi*R ? I know that the center length of the center of the nails is: sqrt((x2-x1)^2 + (y2-y1)^2) but why 2*PI*R ?????? Edited by author 31.10.2004 17:26 Re: Why 2*Pi*R ? help me. i can't solve this problem. Re: Why 2*Pi*R ? 2PiR is length of arc's Re: Why 2*Pi*R ? Послано Machvi 8 фев 2007 02:55 it has a very nice solution Re: Why 2*Pi*R ? Послано svr 8 фев 2007 10:08 You should find explanations to the formula to not it be trick. For example. Let us consider inner normal vector to the boundary - n , moving along boundary. It gets rotation 2*Pi after one circle. But really n rotates only on angles or on archs and total rotation is L/R where L- total length of archs . Thus we have 2*Pi=L/R therefore L=2*Pi*R |
|
|