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| вернуться в форум | Why 2*Pi*R ? I solve that problem but I don't understand why I should take 2*Pi*R ?I know that the center length of the center of the nails is:
 sqrt((x2-x1)^2 + (y2-y1)^2)
 but why 2*PI*R ??????
 
 Edited by author 31.10.2004 17:26
Re: Why 2*Pi*R ? help me. i can't solve this problem.Re: Why 2*Pi*R ? 2PiR is length of arc'sRe: Why 2*Pi*R ? Послано Machvi  8 фев 2007 02:55it has a very nice solutionRe: Why 2*Pi*R ? Послано svr  8 фев 2007 10:08You should find explanations to the formula to notit be trick.
 For example. Let us consider inner normal vector to the boundary - n , moving along boundary. It gets rotation 2*Pi after one circle. But really n rotates only on angles or on
 archs and total rotation is L/R where L- total length of archs . Thus we have 2*Pi=L/R therefore L=2*Pi*R
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