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back to board1000=1^3+0^3+0^3+0^3=1
1=1^3=1
IF THE DISTANCE BETWEEN TWO POINTS = 1 THAT FOLLOWING TOO WILL BE 1.
USE BREAK It is wrong.
"Oh, by the way! The value of SMK is always divisible by 3. It’s normal for Martians – all their numbers are divisible by 3." On another if the previous number is equal to next that break f(153)=1^3+5^3+3^3=1+125+27=153
=)) That's really so! :) Thank you! I've got AC! Its my solution:
[code deleted]
Edited by author 21.06.2007 01:35
Edited by moderator 06.12.2019 20:30 Your prog get AC, but
look at this test:
1
33333 313 1
log of my prog:
2) 55
3) 250
4) 133
5) 55
6) 250
7) 133
8) 55
9) 250
10) 133
11) 55
12) 250
13) 133
14) 55
15) 250
16) 133
17) 55
18) 250
19) 133
20) 55
21) 250
22) 133
23) 55
24) 250
25) 133
26) 55
27) 250
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there is period! And you never get dist[j]==dist[j-1]
And your prog get TLE on my test:
||| 33333
1) ||| 33333 313 1
2) ||| 33333 313 1
3) ||| 33333 313 1
4) ||| 33333 313 1
5) ||| 33333 313 1
i) ||| 33333 313 1
33333) ||| 33333 313 1
But there is no such tests => AC. =)
[code deleted]
Edited by author 02.12.2011 18:57
Edited by moderator 06.12.2019 20:31 313 isn't divisible by 3. |
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