Shut up! Pascal Will Newer Die!

Edited by author 18.10.2006 08:05

In C++ very hard syntax, and Pascal is good language too

Currently I'm using C++ for solving problems, but can say: Pascal foreva! C++ has many drawbacks which are worse than just long "begin .. end"

I solved problems using all languages available on this server and Java seems to be most convenient for me..

It's possible. :-)))

http://acm.timus.ru/status.aspx?space=1&num=1220&author=23793
http://acm.timus.ru/status.aspx?space=1&num=1306&author=23793
1275 is coming soon.

Edited by author 13.02.2009 23:53

And why it is problem to solve it in Java? What we need for solution - just one array int[1000]
But I really don't understand why timelimit is so small - memory is not crucial part of this problem at all...

Maybe author wanted to cut off DP way of solving this problem or something like this.

#include <iostream>
#include <stdio.h>
using namespace std;
int main()
{
    int br[10024],i,m;
    double n,a;
    float sum;
    cin>>n>>a;
    sum=100/a;
    for(i=1;i<=10024;i++)
    {
        br[i]=0;
    }
    for(i=1;i<=a;i++)
    {
        cin>>m;
        br[m]++;
    }
    for(i=1;i<=n;i++)
    {

         printf("%.2lf",(br[i]*sum));
         cout<<"%"<<endl;
    }
    return 0;
}

Holywar on timus=). Lol.

Can anyone translate my solution below into C++? I want to learn programming in C/C++ too :)

type TArray=array of dword;
var arr:TArray;
m,n,c,i:dword;
begin
readln(n,m);
setlength(arr,n+1);
for i:=1 to n do arr[i]:=0;
for i:=1 to m do begin
readln(c);
arr[c]+=1;
end;
for i:=1 to n do begin
writeln((arr[i]*100/m):2:2,'%');
end;
end.