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back to boardShow all messages Hide all messages Edited by author 19.02.2008 00:26 It's part of my code: {...} int i,s=0,p=0; for(i=0;i<n;i++) {cin>>c; p+=c; s+=p; } At the end I use as answer: (n*a+b-2*s)/(n+1), where a means a[0] b means a[n+1] Good luck!!! Edited by author 17.02.2008 19:18 |
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