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back to boardShow all messages Hide all messagesWHAT IS WA#4 Bunyodbek Bobodjanov (TATU UF) 9 Oct 2008 20:50 ADMINSTRATOR HELP PLEASE !!!!!!!!!!!! IT'S MY COD var a:array [1..20010] of char; i,j,k,n,w:integer; r:char; s:string; f:boolean; g:text; t:integer; procedure solve; label 1; var e:integer; begin f:=false; t:=0; for k:=1 to n+i do if (a[k]<>a[n+i-k+1]) then goto 1; f:=true; 1: end; {IMPORTANT PART} Begin assign(g,'input.txt'); reset(g); while not eof(g) do begin readln(g,s); n:=0; for i:=1 to length(s) do begin n:=n+1; a[n]:=s[i]; end; i:=0; repeat solve; if not(f) then begin i:=i+1; for j:=n+i downto n+1 do begin a[j]:=a[j-1]; end; a[n+1]:=a[i]; solve; end; until f; end; // close(g); for j:=1 to n+i do write(a[j]); readln;readln; end. REAL MADRID LUCK THE BEST CLUB Me too!!! program Ural1354; var s:string; a,b,l:longint; begin readln(s); l:=length(s); a:=1; while a<l do begin if s[a]<>s[l] then begin s:=s+' '; for b:=length(s) downto l+2 do s[b]:=s[b-1]; inc(l); s[l]:=s[a]; end; inc(a);dec(l); end; writeln(s); end. You are to find a nonempty word S2 if the input is palindrome... Test#4 abaabaaba ans: abaabaaba //for WA4, because S2 must be not empty! abaabaabaaba //for AC Edited by author 25.11.2011 17:57 I have the same answer, but still get WA4. What the problem? That's not the answer my friend. This is correct: abaabaaba abaababaaba As you see, your solution add three characters. Mine add only two. Greetings! nope, you should print S1 S2, as you see in your answer there is not clearly S1 |
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