Formula
Послано
evjava 31 окт 2009 19:00
Anybody use this? It's right formula or no?
a1:=(n*a(0)+a(n+1)-sum(i=1 to n+1 , c(i)*2^i))/(n+1) ?
Edited by author 31.10.2009 19:00
Re: Formula
Hi,
if n = N+1, then formula is
a1 = an/n + a0*(n-1)/n - sum(i=1, N, 2*(n-i)*ci)
Re: Formula
Послано
Frank 24 май 2010 21:35
Your formula is OK except in
a1 = an/n + a0*(n-1)/n - sum(i=1, N, 2*(n-i)*ci),
the term sum(i=1, N, 2*(n-i)*ci) should divide by n