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вернуться в форумFormula Послано evjava 31 окт 2009 19:00 Anybody use this? It's right formula or no? a1:=(n*a(0)+a(n+1)-sum(i=1 to n+1 , c(i)*2^i))/(n+1) ? Edited by author 31.10.2009 19:00 Re: Formula Hi, if n = N+1, then formula is a1 = an/n + a0*(n-1)/n - sum(i=1, N, 2*(n-i)*ci) Re: Formula Послано Frank 24 май 2010 21:35 Your formula is OK except in a1 = an/n + a0*(n-1)/n - sum(i=1, N, 2*(n-i)*ci), the term sum(i=1, N, 2*(n-i)*ci) should divide by n |
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