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back to boardWA#10 At the moment my way is to look through all the squares of length LEN (using binary search) and to check, whether a hash of a square was met before. It is of O(N*M*log(min{N, M})) complexity. But I get WA#10 again and again. Please, if someone had a problem with this test, share your impressions, 'cause I'm going slightly mad. Re: WA#10 You have a collisions with hash. (I've got this problem also because second number x was to small and close to first one). Re: WA#10 Thank you, it really had to do with collisions. Actually, my self-made hashset implementation was fantastically awful. :-) Edited by author 06.07.2012 15:48 binary search Posted by Anwar 17 Sep 2018 18:51 Why you have used binary search? How we can say that the sq. matrix 2x2 has less value than 3x3. and 3x3 has less than 4x4. how can we justify? |
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