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back to boardCould anyone give me the hint to solve this problem ? But we can't do transformations with antiequations such as with equations. For example, let we have a system:
x1 != 0 (mod 3)
x2 != 2 (mod 3).
It has a solution (2; 0)
If we add the antiequations, we'll get this one:
x1+x2 != 2 (mod 3), but it's wrong for solution (2; 0) of the system!
Am I right?
Edited by author 29.03.2011 00:53 Uhm, sorry. I was wrong. I think that your advice is absolutely right!
Let for example det(Aij)<>0.
Then Answer is 2^k,because (A*X)i in {0,1,2}\{bi}
If det(Aij)==0
we can use gauss method to make standard worm of the matrix A. |
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