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back to boardBe sure that(at least for the given interval, [4,2*10^9]) every even number can be shown as sum of two prime numbers.
1. if n is prime, {n}
2. if n is even, {n = p1 + p2}
3. if n is odd {n = 3 + p1 + p2} ( n-3 is even, so that recall second case.)
For convenience, prime numbers under 10^5 can be initialized.
Edited by author 03.12.2012 03:00
Edited by author 03.12.2012 03:00 prove it :) If he could proof it, he would get 1 thousand million dollar
Edited by author 02.08.2015 20:59 > if n is odd {n = 3 + p1 + p2} ( n-3 is even, so that recall second case.)
IMO this is wrong. 85 = 2 + 83 is the counter-case.
> For convenience, prime numbers under 10^5 can be initialized.
this way too big. :)
Edited by author 12.01.2019 19:53
Edited by author 12.01.2019 19:54 |
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