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вернуться в форумПоказать все сообщения Спрятать все сообщенияWA#1 elf 21 апр 2013 16:01 It works on my computer, but judgement result is Wrong Answer.
#include <stdio.h>
#include <math.h>
#define MAXSIZE 65536
int main()
{
unsigned long int value = 0;
int counter = -1;
int i = 0;
unsigned long int a[MAXSIZE];
while (scanf("%lu", &value) != EOF)
{
a[++counter] = value;
}
for (i = counter; i > -1; i--)
{
printf("%.4f\n", sqrt((double)a[i]));
}
return 0;
}
Edited by author 21.04.2013 19:50 be confirmed that input limit is covered by your program Try to use unsigned long long, because 10^18>2^32 the array is too small,you can try global array to solve it ,but it should be large,at least
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