#include<stdio.h>
#include<math.h>
int main()
{
    int  n;

    printf("%d\n",scanf("%d",&n)*n*scanf("%d",&n)*n*scanf("%d",&n)*n*2);
}

you write so complex, the answer is N*A*B*2

why so complex man!!

Should it work at all? Isn't it unspecified behavior - n is modified 3 times in the same expression?

Brother, you should solve it step by step!Don't do all things in printf function.In this way u can easily find you bug!

You can follow this method n*a*b*2