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Discussion of Problem 1068. Sum

ac (cpp)
Posted by lhyx1990 26 Jan 2014 15:51

#include <iostream>
using namespace std;
int main(int argc, const char * argv[])
{
    int n;
    cin >> n;


    if (n >= 1) {
        cout << n * (n + 1) / 2;
    }
    else {
        cout << - (-n * (-n + 1) / 2) + 1;
    }

}