Sample numbers have different value of math.sqrt() in last digit. Why? This task is not so big level for hidden problem.

 sample result:
2297.0716
936297014.1164
0.0000
37.7757

my result:
2297.0715
936297024.0000
0.0000
37.7757

import java.io.PrintWriter;
import java.util.Scanner;
import java.util.*;

public class AlgorithmTAsk {

    public static void main(String[] arg){

        Scanner in = new Scanner(System.in);
        PrintWriter out = new PrintWriter(System.out);
        ArrayList<Float> f = new ArrayList<Float>();

        while (in.hasNextLong()) {
            f.add((float) Math.sqrt(in.nextLong()));
        }

        for(int i = f.size()-1;i>=0;i--){
            out.printf("%8.6f\n",f.get(i));

        }

        out.flush();
    }
}

Edited by author 19.04.2016 19:45

Try double instead of float

import java.util.Scanner;
import java.text.DecimalFormat;
import java.lang.StringBuffer;
import java.lang.Math;
public class Timus2{
    public static void main(String[] args){
        Scanner S = new Scanner(System.in);
        DecimalFormat df = new DecimalFormat("#.0000");
        StringBuffer result = new StringBuffer();
        while(S.hasNext()){
            result.append(df.format(Math.sqrt(S.nextDouble())) + "\n");
        }
        S.close();
        System.out.println(result);
    }
}

1) Any advantages of using "StringBuffer result"?
Is it really faster then just print result line by line?

2) Show here expected output, your program output, compare.