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back to boarda hint Posted by esbybb 14 Oct 2016 21:07 long ans[] = new long[23]; ans[2]=lim[2]; for (int i=4; i<=20; i+=4) { int half=i/2; ans[i]=lim[half]*lim[half]; ans[i+2]=lim[half]*lim[half+2]; } System.out.println(ans[N]); Re: a hint Posted by esbybb 14 Oct 2016 21:08 lim stands for the "lucky in Moskva" |
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