----
ll l,r;
    cin >> l >> r;
    if(l==1){
        cout << 1;
        return 0;
    }
    if(l == r){
        cout << l;
        return 0;
    }
    ll n = 1e6+2;
    vector<bool> prime(n+1,1);
    prime[0]=prime[1] = 0;
    for( ll i =2; i*i <= n; i++)
    {
        if(prime[i])
        {
            for(ll j = i*i; j <= n; j+=i)
                prime[j]=0;
        }
    }

    for(ll i = r; i >= l; i--){
        if(prime[i])
        {

            cout << i;
            return 0;
        }
    }
    double mx =1e11;
    ll ans = 0;
    for(ll i = r; i >= l; i--){

        if(i % 2 == 0)
            continue;


        double suma = 1;
        for(ll k = 2; k*k <= i; k++){

            if( i % k == 0 ){
                suma += k;
                if(i/k != k){

                    suma += (i/k);
                }
            }
        }

        double q=(suma)/(i);


        if( q < mx){
            mx = q;
            ans = i;
        }

    }
    cout << ans;
    return 0;
----

I used the sieve of Eratosthenes to find prime numbers. If I have not found prime numbers on the interval [l; r], then I iterate over all numbers with [l; r]. I go through the divisors (sqrt (i)). I calculate the minimum. What's wrong? WA 11. Google translator, sorry.