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вернуться в форумWhy I get WA? Pelase, help me!!!!!!! There is my program Program t1007; Type BigM=array[1..1500]of byte; Var Mas1,Mas2 :BigM; ch :char; N,i,j,C,m,l :integer; Function Sum(X:BigM):boolean; Var S,i :longint; begin S:=0; for i:=1 to n do if X[i]=1 then S:=S+i; Sum:= (S mod (N+1)) = 0; end; begin Readln(N); C:=0; repeat c:=c+1; ch:=' '; m:=0; while (ch<>#13)and(ch<>#10)and(ch<>#26) do begin read(ch); if (ch<>#13)and(ch<>#10)and(ch<>#26)and(ch<>#32) then begin m:=m+1; if ch='0' then Mas1[m]:=0; if ch='1' then Mas1[m]:=1; end; end; if m=0 then c:=c-1 else begin if m=n then begin Mas2:=Mas1; if not(Sum(Mas2)) then i:=0; repeat i:=i+1; if i>1 then Mas2[i-1]:=Mas1[i-1]; Mas2[i]:=0; until Sum(Mas2); for i:=1 to n do write(Mas2[i]);writeln; end; {/--------/} if m-1=n then begin for i:=2 to n do begin l:=0; for j:=1 to n+1 do if i<>j then begin l:=l+1; Mas2[l]:=Mas1[j]; end; if Sum(Mas2) then break; end; for i:=1 to n do write(Mas2[i]);writeln; end; if m+1=n then begin l:=0; repeat l:=l+1; for i:=1 to l-1 do Mas2[i]:=Mas1[i]; Mas2[l]:=1; for i:=l to m do Mas2[i+1]:=Mas1[i]; if Sum(Mas2) then break; Mas2[l]:=0; if Sum(Mas2) then break; until False; for i:=1 to n do write(Mas2[i]);writeln; end; end; until seekEOF; end. |
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