|
|
back to boardWhy I got WA? Posted by qwt 12 Feb 2002 07:01 var n,l:integer; s:array[0..1001] of 0..1; z:char; procedure print(a,b:integer); var i:integer; begin for i:=a to b do write(s[i]); end; procedure work(l,n:integer); var i,j,k:longint; a:array[0..1001] of integer; begin fillchar(a,sizeof(a),0);k:=0; for i:=1 to l do begin inc(a[i],a[i-1]+ord(s[i])-ord('0')); if s[i]=1 then begin inc(k,i);k:=k mod (n+1);end; end; inc(k,n+1); if l<n then begin if k mod (n+1)=0 then begin print(1,l);writeln(0);exit;end; for i:=l downto 1 do if (k+a[l]-a[i-1]) mod (n+1)=0 then begin print(1,i-1);write(0);print(i,l);writeln;exit; end else if (k+a[l]-a[i-1]+i) mod (n+1)=0 then begin print(1,i-1);write(1);print(i,l);writeln;exit; end; end else if l=n then begin if k mod (n+1)=0 then begin print(1,l);writeln;exit;end; for i:=1 to n do if (s[i]=1)and( (k-i) mod (n+1)=0) then begin s[i]:=0;print(1,l);writeln;exit; end; end else begin for i:=1 to l do if (s[i]=1)and((k-a[l]+a[i+1]-i) mod (n+1)=0) then begin print(1,i-1);print(i+1,l);writeln;exit; end else if (s[i]=0)and((k-a[l]+a[i+1]) mod (n+1)=0) then begin print(1,i-1);print(i+1,l);writeln;exit; end; end; end; begin readln(n); while not(eof) do begin l:=0; fillchar(z,sizeof(z),0); while not(eoln) do begin inc(l); read(z); if z='1' then s[l]:=1; end; readln; work(l,n); end; end. |
|
|