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Обсуждение задачи 1193. Очередь на зачёт

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What change if shift beginning time of the exam to more early
time ? Please explain to me. Thank!
> What change if shift beginning time of the exam to more early
> time ? Please explain to me. Thank!

70  +  40  =  110 // first student (70 40 150)
110 +  15  = 125  //second one      (99 15 400)
125 +  10  = 135  // third one (100 10 120),
  he is 15 min late, (he's to be free at 120)

i hope it helps.
Re: I don't understand problem 1193. Please help me! MadPsyentist/Sam 3 мар 2002 00:09
> > What change if shift beginning time of the exam to more early
> > time ? Please explain to me. Thank!
>
> 70  +  40  =  110 // first student (70 40 150)
> 110 +  15  = 125  //second one      (99 15 400)
> 125 +  10  = 135  // third one (100 10 120),
>   he is 15 min late, (he's to be free at 120)
>
> i hope it helps.
>
does this mean third should start at 110 and second start at
110+10=120?
> > > What change if shift beginning time of the exam to more early
> > > time ? Please explain to me. Thank!
> >
> > 70  +  40  =  110 // first student (70 40 150)
> > 110 +  15  = 125  //second one      (99 15 400)
> > 125 +  10  = 135  // third one (100 10 120),
> >   he is 15 min late, (he's to be free at 120)
> >
> > i hope it helps.
> >
> does this mean third should start at 110 and second start at
> 110+10=120?

students should start the exam as fast as they are ready (by the order
of T1)
so second student cannot enter the room after third one ( i suppose ;)
)
arrghh i'm sorry. i still not understand the problem MadPsyentist/Sam 3 мар 2002 02:18
if the input is
4
100 10 120
70 40 150
99 15 400
101 50 160
what's to output and why
Solution:

1st) #2 starting at 70 ending at 110
2nd) #3 starting at 110 ending at 125
3rd) #1 starting at 125 ending at 135  (a +15 shift)
4th) #4 starting at 135 ending at 185  (a +25 shift)

That way the answer should be 25

> if the input is
> 4
> 100 10 120
> 70 40 150
> 99 15 400
> 101 50 160
> what's to output and why
> if the input is
> 4
> 100 10 120
> 70 40 150
> 99 15 400
> 101 50 160
> what's to output and why

let's see

70  + 40 = 110 (70 40 150)
110 + 15 = 125 (99 15 400)
125 + 10 = 135 (100 10 120) 15 min late
135 + 50 = 185 (101 50 160) 25 min late

if examenator shifts the beginning of the exam by 25 minutes then
every student will pass the exam before T3.





thank you very much MadPsyentist/Sam 3 мар 2002 15:43
> if the input is
> 4
> 100 10 120
> 70 40 150
> 99 15 400
> 101 50 160
> what's to output and why
Thank you hajime, I got AC.
you are wrong Oleg 29 дек 2002 09:25
70  +  40  =  110 // first student (70 40 150)
110 +  10  = 120  //second one      (100 10 120)
129 +  10  = 139  // third one (99 15 400),
 he is free at 139?
 wait =0;
Re: you are wrong Locomotive 13 янв 2003 18:38
> 70  +  40  =  110 // first student (70 40 150)
> 110 +  10  = 120  //second one      (100 10 120)
> 129 +  10  = 139  // third one (99 15 400),
>  he is free at 139?
>  wait =0;
Oleg i think
thirs student comes in queue before second
as his t1 is 99 and thirds is 100
agree?
Re: you are wrong ZhengYuhang 10 авг 2007 18:32
Thank all the people above!
Re: you are wrong Vo Minh Hien 15 авг 2010 14:01
Thanks all. I got AC