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вернуться в форумCan anybody check my program? It seems to be very simple, but my solution fails. Here is my solution: #include <fstream.h> #include <math.h> int main() { // p*(2*a+p-1) = 2*n ==> long n; cin>>n; n*=2; for(long p=sqrt(n); p>1; p--) if(n%p==0) if(n/p>p && (n/p-p)%2) {cout<<(n/p-p+1)/2<<' '<<p<<endl; return 0;} return 0; } Best regards! I know why ur solution fails! :) > Here is my solution: > > #include <fstream.h> > #include <math.h> > > int main() > { > // p*(2*a+p-1) = 2*n ==> > long n; cin>>n; n*=2; > for(long p=sqrt(n); p>1; p--) <====== p == 1 ??? > if(n%p==0) if(n/p>p && (n/p-p)%2) > {cout<<(n/p-p+1)/2<<' '<<p<<endl; return 0;} > return 0; > } > > Best regards! Thank you! I got AC. I always fail with such a stupid errors.
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