Обсуждение @ 1152. Кривые зеркала @ Timus Online Judge

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How to get AC with 0.02 s (mine is 0.7 s)??(-) Miguel Angel 18 апр 2002 03:24

Thanks :)

Re: How to get AC with 0.02 s (mine is 0.7 s)??(-) zrp 21 дек 2008 07:01

maybe you need to DP

Re: How to get AC with 0.02 s (mine is 0.7 s)??(-) Ignorance 23 дек 2008 17:11

I used bitwise operations (we can represent each subset as number between 1 and 2^n - 1), this AC'ed with 0.031s, may be you can further improve it ..

Re: How to get AC with 0.02 s (mine is 0.7 s)??(-) Artem Khyzha 27 июл 2011 20:14

Well, I used DP on subsets, but can't get faster than 0.093. Is there any special trick?

Re: How to get AC with 0.02 s (mine is 0.7 s)??(-) Ainan Ahmed 9 июн 2017 22:18

I used bitmask... AC on 0.015

Re: How to get AC with 0.02 s (mine is 0.7 s)??(-) imaginary friend 17 авг 2018 02:15

probably they just upgraded the machine from 2011, that's why you are faster than others :P

Re: How to get AC with 0.02 s (mine is 0.7 s)??(-) Viktor Krivoshchekov`~ 28 ноя 2019 15:20

I get 0.015 and used queue for each recount

Обсуждение задачи 1152. Кривые зеркала