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вернуться в форумDo not seek any kind of logic in this problem just paste this! (+) I think that there must be some 'X' one after another, because it is said 'ai*X^(n-1)' like this for n=2:   0 X X * * 1 --> I'm only not quite sure for this '1' X * --> and if there is no '1' this row also turns off + 2 +     I have tried to write something but it sucked, so I got a Pascal code and turned it to C++!   AC 0.02 sec   /////////////////////////////////////////////// // 1059   #include <stdio.h>   int i,n;   int main() {   scanf("%d",&n); puts("0");   for (i=1;i<=n;i++)     printf("X\n*\n%d\n+\n",i);   //getch();   return 0; } /////////////////////////////////////////////////  |  
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