Why when i submit my program with sqrt(2), it makes compilation error?(-) Could You please explain the sample to me ? -> is the diagonal multiplied by sqrt(2) ??? Explanation of sample(+) It tells
1 1
1 3
4 1
4 3
Then you will go from
(1,1)->(2,1)->(3,2)->(2,3)->(1,3) = 2 + 2*sqrt(2) /*two diagonals*/
(1,3)->(2,3)->(3,2)->(4,1) = 1 + 2*sqrt(2) /*two diagonals*/
(4,1)->(4,2)->(4,3) = 2
Add up this distance and divide by V, you'll get the answer.
But i use:
#include<math.h>
const double sqrt2 = sqrt(2);
and makes me Compile Error :(, so just change for a numerical one and
get AC. Thank You ery much ! > It tells
> 1 1
> 1 3
> 4 1
> 4 3
> Then you will go from
> (1,1)->(2,1)->(3,2)->(2,3)->(1,3) = 2 + 2*sqrt(2) /*two diagonals*/
> (1,3)->(2,3)->(3,2)->(4,1) = 1 + 2*sqrt(2) /*two diagonals*/
> (4,1)->(4,2)->(4,3) = 2
> Add up this distance and divide by V, you'll get the answer.
> But i use:
>
> #include<math.h>
>
> const double sqrt2 = sqrt(2);
>
> and makes me Compile Error :(, so just change for a numerical one
and
> get AC. Thank You very much ! > It tells
> 1 1
> 1 3
> 4 1
> 4 3
> Then you will go from
> (1,1)->(2,1)->(3,2)->(2,3)->(1,3) = 2 + 2*sqrt(2) /*two diagonals*/
> (1,3)->(2,3)->(3,2)->(4,1) = 1 + 2*sqrt(2) /*two diagonals*/
> (4,1)->(4,2)->(4,3) = 2
> Add up this distance and divide by V, you'll get the answer.
> But i use:
>
> #include<math.h>
>
> const double sqrt2 = sqrt(2);
>
> and makes me Compile Error :(, so just change for a numerical one
and
> get AC. Re: Thank You very much ! you should use sqrtl(2) Re: Thank You very much ! Or .. you should use a "static_cast" it can be done easily this way :
const double sqrt2 = sqrt((double)2);
because sqrt , takes an arugment type double. I hope I helped. |
