Please, help me understand, how turn on printf and scanf in my program.
If I write :
int Solution (int n, int a, int b)
{
    return (2*n*a*b);
}

int main()
{
    int n,a,b;
    scanf ("%d %d %d", &n, &a, &b);
    printf ("%d", Solution (n,a,b));
    return 0;
}

system will throw "Compilation error" with
vtje2d-4h6iqg.cpp(9) : error C3861: 'scanf': identifier not found
vtje2d-4h6iqg.cpp(10) : error C3861: 'printf': identifier not found.

If i write the same, with #include "stdafx.h" on the top, system will throw "Compilation error" with
rvkkio-7db2pu.cpp(4) : fatal error C1083: Cannot open include file: 'stdafx.h': No such file or directory

var
  n: integer;
begin
  readln(n);
  if (n>=1) and (n<=4) then
    writeln('few');
  if (n>=5) and (n<=9) then
    writeln('several');
  if (n>=10) and (n<=19) then
    writeln('pack');
  if (n>=20) and (n<=49) then
    writeln('lots');
  if (n>=50) and (n<=99) then
    writeln('horde');
  if (n>=100) and (n<=249) then
    writeln('throng');
  if (n>=250) and (n<=499) then
    writeln('swarm');
  if (n>=500) and (n<=999) then
    writeln('zounds');
  if n>=1000 then
    writeln('legion');
end.

My program works fine in console, but for some reason I get wrong answer on test 9. Could someone point out where is the problem in my code?

#include <iostream>
#include <vector>
#include <math.h>
#include <iomanip>

using namespace std;

int main()
{
    double num;
    vector<long long> input;
    int limit  = 256 * 1024 / sizeof(long long);
    for (int k = 0; (cin >> num) && k <= limit; k++)
    {
        if (num != (long long)num || num < 0 || num > pow(10.0, 18))
            return 0;
        input.push_back((long long)num);
    }
    for (int i = input.size() - 1; i >= 0; i--)
        cout << fixed << setprecision(4) << sqrt(input[i]) << endl;

    return 0;
}

Edited by author 28.03.2016 23:17

Edited by author 28.03.2016 23:18

Edited by author 28.03.2016 23:18

Никак не пойму,что обозначает "Во всех тестах, кроме первого, расстановки зашифрованы. Вы не должны пытаться расшифровывать эти данные (и не обязаны их считывать), однако наличие во вводе этой информации позволяет нам гарантировать, что в этой задаче заранее определённые тесты, которые не подстраиваются под вашу стратегию."
Как выглядят эти данные и влияют ли они на решение?
И вопрос тем,кто решил-всегда ли мы можем "угадать в среднем",что у нас в очередной игре ровно один 0(или 1)?

P.S. Пока дошёл только до 70 теста
P.S. Уже решил.Не заметил одну особенность.

Edited by author 25.10.2015 00:00

Lost ac. WA 17

Looks like it isn't "n<=0", it isn't about integer overflow during even-length sequence overflow calculation.

Hi ,
What IDE or Editor or Online Interpreter do you guys use for Python?

Please help!

Thanks in advance

Why constraints are so small?

My algo is O(max(a,b,c)).

I always WA#2



Edited by author 27.02.2016 15:28

Edited by author 27.02.2016 15:30

Is it a special case ?

Do strings consist of only lower-case letters of latin alphabet ?

New tests were added. About 160 solutions got WA verdict on them.

Why? My solution is ok when i run with other tests that i have seen in this forum, but when i submit here, i get WA#1!

Is there a problem about the output?

Thanks.

Тест №8. Какой должен быть ответ?

var
  t: real;
  n, k, i,j: integer;
  a:array [1..101] of integer;

begin
  readln(n);
  for i := 1 to n do
  begin
    read(a[i]);
  end;
  for i:=1 to n do
  begin
    for j:=1 to n do
    begin
    if a[i]<a[j] then
    begin
      swap(a[i],a[j]);
    end;
    end;
  end;

  for i:=1 to (n div 2)+1 do
  begin
    t:=t+((a[i] div 2)+1);
  end;

  write(t);
end.

What was pretty interesting problem. Ty

Edited by author 26.03.2016 17:18

var t1,t2,i,k,q:integer;
a:array [1..10000000] of integer;
begin
read(t1,t2);
for i:=1 to 10 do
        read(a[i]);
for i:=1 to 10 do
        begin
        if a[i]>0 then k:=k+a[i];
        end;
if t1<t2 then
        begin
        q:=(k*20)+t1;
        if q<=t2 then write('No chance.')
        else if q>t2 then write('Dirty debug :(');
        end
else if t1>=t2 then
        begin
        write('No chance.');
        end;
end.

Edited by author 01.11.2014 13:12

Edited by author 01.11.2014 13:12

In example we have:
7 soldiers
1 - commander
2 - Ki = 1, Ci = 10
3 - Ki = 2, Ci = 5
4 - Ki = 2, Ci = 3
5 - Ki = 3, Ci = 1
6 - Ki = 4, Ci = 2
7 - Ki = 5, Ci = 3
It's right?
Now, by a problem A1 === 1, A5 = A6 = A7 === 0.
A2, A3 and A4 - may be either 0 or 1, yes?
if A2 = 1 and A3 = 0 and A4 = 1 then profit = C7 * |A7 - A3| + C6 * |A6 - A3| + C5 * |A5 - A3| + C4 * |A4 - A2| + C3 * |A3 - A2| + C2 * |A2 - 1| = 3 * 0 + 2 * 0 + 1 * 0 + 3 * 0 + 5 * 1 + 10 * 0 = 5
Then answer min profit = 5.
But in example is 8.00
I understood! 4 - it's soldier too and his A4 === 0 too

Edited by author 25.03.2016 21:20

Just missed :( and WA))