what is answer for that test
5 -9
4 -8 -6 1 -10
?

Can you suggest what is causing this error.

N = int(input())
s = [0]

for i in range(N):
   k = int(input())
   s.append(int(s[i] + k))

Q = int(input())
while Q:
   l, r = map(int, input().split())
   print(s[r] - s[l-1])
   Q -= 1

35
15 2 0
6 0
8 15 0
18 4 0
18 0
7 0
13 0
24 1 0
24 0
22 21 0
4 15 0
15 11 0
26 0
31 21 0
32 2 0
2 0
13 1 0
29 4 0
5 8 0
28 18 0
8 16 0
8 27 0
29 18 0
13 26 0
1 0
14 0
25 35 0
10 25 0
3 0
23 9 0
1 8 0
19 26 0
10 20 0
33 0
26 0
27 16

ans:12

28
5 0
15 0
8 22 0
23 20 0
6 19 0
1 22 0
9 28 0
14 15 0
5 0
7 18 0
18 0
16 0
27 0
8 0
27 0
19 3 0
24 8 0
2 25 0
22 0
15 12 0
8 5 0
12 0
6 0
2 9 0
25 0
9 9 0
9 0
2 0
19 15

ans:4

38
19 36 0
15 0
23 0
17 0
9 0
34 0
13 10 0
15 0
15 4 0
26 0
5 33 0
34 0
9 0
29 0
4 0
4 20 0
24 0
3 38 0
27 0
22 7 0
35 27 0
8 0
34 36 0
5 33 0
22 7 0
18 26 0
26 17 0
22 0
12 0
27 0
8 8 0
35 0
24 0
31 0
23 0
6 0
18 0
16 27 0
9 35

ans:7

37
34 0
16 3 0
24 0
14 24 0
33 18 0
17 0
33 32 0
18 16 0
19 1 0
8 0
29 34 0
1 25 0
7 3 0
28 0
34 0
1 21 0
36 0
18 0
36 21 0
27 0
14 0
15 5 0
33 0
9 32 0
35 14 0
22 1 0
18 35 0
6 0
30 0
1 2 0
30 0
20 0
18 0
30 0
30 0
11 0
15 37 0
1 6

ans:4

I hope they can help you~

Edited by author 26.08.2009 18:29

Help me: Wrong answer in test #6

Wrong answer in test №20, help

Edited by author 10.03.2022 01:08

what's the test case 7???? All the cases given hv been passed alr...

#include <iostream>
using namespace std;

int main() {
    int n, k, *arr,raz,y=0,ost=0;
    cin >> n >> k;
    arr = new int[n];
    for (int i = 0; i < n; i++) {
        cin >> arr[i];
    }
    for (int i = 0; i < n; i++) {
        raz = 5 - arr[i];
        if (raz >= 0) {
            y = y + raz;
        }
        else {
            y = y;
            ost = ost + raz * -1;
        }
    }

    cout << ost << " " << y;
    return 0;
}

try
12.12.12
1
Not a floating point number

5 7
1 2
2 3
1 4
4 5
1 5
2 5
4 3
4
3 4 7 2

ans: 1 1 2 3

On the first sight i thought i'd need O(3 ^ 16) but the problem is much easier.

if you WA on #3 ,please use unsigned __int64 and high-accuracy
if you WA on #9 ,try this

2
10
3

The answer is 0

Edited by author 03.03.2022 10:56

cnt = 0
a = int(input())
a1 = list(map(int, input().split()))
b = int(input())
b1 = list(map(int, input().split()))
c = int(input())
c1 = list(map(int, input().split()))
for i in a1 :
    if i in b1 and c1 and a1 :
        cnt += 1
print(cnt)

what is wrong? tells "wrong answer"

Probably you're getting overflow

Arithmetic average is not exacltly x. Due to the rounding arithmetic average can be x + 0.01 or even x + 0.04999

\/ \/
/\ /\

8 4
0 0
2 2
2 0
0 2
0 3
2 5
2 3
0 5
1 2
3 4
5 6
7 8

Answer: "NO"

Spent a hour to realise that you don't need to count left and right parts of figure, only middle

Edited by author 27.02.2022 15:58

I investigated on internet, but most of the answers were putting a type of character that breaks the cycle, but in the input example there´s no character and it´s not enough with a "while(cin >> n)" pls help