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| new task | Dmi3Molodov | | 15 июл 2026 05:02 | 1 |
2^8 queries are given. Each query has an interval [L,R). (2^63<L,R<2^64) Find the number of primes in each interval.
P.S.
Warning:
you won't fit into a hundred lines of code! |
| right answer for test? | ilya trofimov | 2013. Не взбалтывать и не смешивать | 14 июл 2026 10:11 | 3 |
2
0 1 2
1 1 1
-------
unknown unknown
unknown 1
or
1 1
1 1
Before first visit pub #1 is asking about drinks? unknown unknown
unknown 1
Beacuse he doesn't know whether he drank 1 or 0 cocktails last time.
And, yes, he will be asked first time. That also means that the trip doesn't stop when answer is unknown |
| WA3 | andreyDagger`~ | 2013. Не взбалтывать и не смешивать | 14 июл 2026 10:10 | 2 |
WA3 andreyDagger`~ 10 янв 2023 20:54 Test:
10
2 3 2 3 6
0 1 1
0 2 4 10
0 3 5 7 9
0 1 3
0 1 3
0 1 8
0 1 7
1 1 7
2 1 5
Answer:
unknown 2
2 2
2 2
2 2
2 2
2 2
unknown unknown
unknown unknown
2 1
2 2 This test looks incorrect as they can't reach any bar after 1 |
| Algo? | melkiy | 1689. Рыболов и штанга | 14 июл 2026 08:29 | 4 |
Algo? melkiy 6 мар 2009 04:35 My step-by-step barbell moving (though improved to add into under and out under the barbell only "right" worms without checking every worm) gives TLE on 8th test.
Is segment tree needed? I solved without it.I also used "improved step-by-step barbell moving",but my solution was quite far from TLE. I modeled groove as int array,but if you use sorting on worms array and then search there some coordinates then you can possibly get TLE.
Edited by author 06.03.2009 05:20 I solved this problem without sorting. I found difference
d[this_step]=count[this_step]-count[prev_step],
and after that
count_squash_worm=count_squash_worm+d[this_step].
Edited by author 09.03.2009 15:06 Just slide ahead and once you step on a worm by left or right plate, increase number of times that worm was stepped on (that number will drift between 0, 1, 2). When number of plates intersecting the worm changes between 0 and 1, total amount of affected worms changes accordingly. This algo can support overlapping worms and 1e+9 coordinates with sorting of worm endpoints. |
| Some info about this problem | Olzhas aka Whale2dy | 1030. Титаник | 14 июл 2026 07:37 | 11 |
Hello, everyone. Just wanted to summarize some info about this problem. Ok, my code got AC with following things in it: 1. My pi was 3.1415926535897932384626433 (perhaps it is enough) 2. I used this formula from wikipedia deltaArc=acos(sin(phiA)*sin(phiB)+cos(phiA)*cos(phiB)*cos(deltaL)); distance = deltaArc*3437.5; (see the first formula from wikipedia http://en.wikipedia.org/wiki/Great-circle_distance)3. I used the following condition: if(100.00-distance>0.005) printf("DANGER!\n"); Hope it will help somebody. thanks a lot ...your formula is really useful.^_^ Used everynth what is written here. However still WA8.
Any new ideas?... Do u know that pi can be calculated by this formula: atan(1) * 4? Also if you use acos on dot-product to get distance over sphere, beware that acos(-1.000000001) or acos(+1.000000001) will give NaN, so clamp argument to [-1, +1] range explicitly. |
| Help WA Test #7 | Varun Sharma | 1030. Титаник | 14 июл 2026 07:35 | 5 |
Edited by author 07.03.2010 10:26 Hi,
Alright guys I have solved the problem. Being a newbie to c# caused me to submit program 35 times. I didn't realize that Math.Round() function will change 100.00 to 100 instead. Here are the lines which I changed.
double miles = distance(ship_latitude_radian, ship_longitude_radian, iceberg_latitude_radian, iceberg_longitude_radian);
if (Math.Round(miles, 2) < 100.00)
{
Console.WriteLine("The distance to the iceberg: {0:F2} miles.", miles);
Console.WriteLine("DANGER!");
}
else
{
Console.WriteLine("The distance to the iceberg: {0:F2} miles.", miles);
} Solved by making the following comparison in java:
if (Math.round(distance*100) < 10000) {
System.out.println("DANGER!");
}
it will force it to compare with 2 digits precision.
Edited by author 14.07.2026 14:28 |
| wrong constant of earth | yyll | 1030. Титаник | 14 июл 2026 07:11 | 2 |
diameter of 6875 miles (/ 2 = 3437.5)???
the mean radius of earth is 6371.0 km (3958.8 miles) Nautical miles are different |
| On WA8 | Solver | 1569. Сети в Исети | 14 июл 2026 06:14 | 1 |
On WA8 Solver 14 июл 2026 06:14 You have to check all edges between centroids, not just arbitrary one. Although it leads to O(N^4) due to N^2 BFSes on cliques, early cutoff on max-dist from roots vs. current result makes it almost O(N^3). AC 0.046 sec |
| Notice | Solver | 1569. Сети в Исети | 13 июл 2026 11:04 | 1 |
Notice Solver 13 июл 2026 11:04 You may output edge nodes in any order (1 2) or (2 1) checker accepts that |
| Who know how the 2nd test looks like?? | Last_Vikings | 1546. Сортировка по-японски | 12 июл 2026 08:40 | 19 |
We cannot imagine the test where our prog will give wrong answer! I wonder too, always wa on test 2 1w1
01w01a
Edited by author 24.04.2007 19:29 No, its not 2nd test. My prog correctly process it, but stil WA2. sorted:
01w01
01w1
01w01a
z000
z00
z00p
z0p
and one more
0
0p
01
1
1p
Edited by author 25.04.2007 20:03 Try this test:
z0p
z00pp
z0pp
z00pp00
z000pp01
z00pp01
z0pp01
z001pp00
z01pp00
z1pp00000
z01pp01
z1pp001pp0
z1pp01pp000
I get WA#2 too. Huge thanks to Alexander Kouprin, after running his test and solving the problem I got accepted. Test from Alexander Georgiev also helped me a lot. By the way, my program gives other output for some test from this thread. Here they are:
abc00125a
abc0125a
abc00125b
abc0125b
abc000000000000000000000125a
abc00000000000000000000125a
abc0012000000000000000000000000005b
abc012000000000000000000000000005b
These tests have almost broken my mind while I have been thinking why they are correct and I'm happy that I do not have to fix my program because of them. Zeroes matters only if strings are equal.
Try this:
abc0125a
abc00125a
abc00125b
abc0125b Try this:
abc0125a
abc00125a
abc00125b
abc0125b I suppose the last test by Peter Huggy is the most similar to second test but after all this tests WA6 Try this: abc00000000000000000000125a abc000000000000000000000125a abc0012000000000000000000000000005b abc012000000000000000000000000005b I suppose the last test by Peter Huggy is the most similar to second test
but after all this tests WA6 Got AC, thanks to Alias tests :) You can also try:
0000000
000
(Already sorted) Your program must return for these tests next results (alredy sorted):
1)
000
00
0
2)
00
0
000a
3)
00a000
00a0 I don't understand this.
Why is 0000000 smaller than 000? What's the logic behind it?
Edited by author 12.01.2021 22:30 I think logic behind it is when strings are equal on "japanese" interchanging alpha-numeric sequences, then the whole strings are compared, so that puts 001 before 01 and 002 before 02. Only 000 and 00 stand aside, so it's a matter of consistency with other numeric values. Or think of it the other way - append something like '~' (ASCII 126) to the end of the sting, that will put 001~ before 01~ and 000~ before 00~ |
| what mean "lexicographically first compatible pair" ? | dibrov.bor[SumySU] | 1530. Ones and Zeroes | 12 июл 2026 04:21 | 4 |
I try to output zeros in this case, but seems like I'm wrong
please show me some example
for example for this case
2
11
11
Edited by author 11.12.2007 21:50 This test is correct, and the answer should be
00
00 The test is correct, original sequences do not need to be compatible |
| A hint ? | Yosif Yosifov | 1530. Ones and Zeroes | 12 июл 2026 04:19 | 10 |
A hint ? Yosif Yosifov 20 фев 2007 01:33 Can someone give me a little hint, please ? make 2 sequences (s1 and s2) such that s1[i]+s2[i]<>2 My solution is based on a greedy approach. I think that an algorithm has many special cases.
Main rool:to correct firstly s2[i] from 1 to 0 in
pair s1[i]=1 and s2[i]=1 diminishing B
but have pair 0, 0 in older position correcting it to 0, 1
for final increasing lexiographicly of B
Who can find all cases he solve the problem After getting AC i have counted 6 cases
next tests correspong each of cases
4
1011
0011
1011
0100
4
1010
0111
1011
0000
4
1011
0110
1100
0000
4
1111
0101
0000
0000
4
1010
0101
1011
0000
4
1011
0100
1100
0000
Edited by author 21.02.2007 13:58 My program successfully passed all of your test cases, but I still WA3... What can it be??? You are need in additional tests
Best if you will create them yourself I have only 3 cases
1) attempt to build a >b
2) attempt to build a+1 0
3) build 0 0 A + B = A XOR B iff there is no carry, or in other words A AND B = 0
So the algo is simple
Find leftmost x such that p[x]=q[x]=1. if none, assume x=n+1.
Find rightmost y to the left of x such that p[y]=q[y]=0. If none, output p+1, 0 (p+1 may become 0). Otherwise set q[y]=1, and q[y+1..n]=0
Edited by author 12.07.2026 04:38 |
| Overrated | Keworker `~ | 1154. Сражение магов | 11 июл 2026 09:16 | 2 |
This task has some problems with accurancy, but 878 is too big rating for it. Agreed. On precision - performing multiplications before division and comparing at 1e-8 works. |
| Need Clarification! | Lebedev_Nicolay[Ivanovo SPU] | 1277. Cops and Thieves | 11 июл 2026 07:27 | 4 |
Can anybody expalain me this problem? I think that in both samples answer is YES, because all vertices are next to refuge or to museum. At last I've solved it.
what about solution:
1) for maxflow use RelabelToFront
2) WA 36 : try this test
5
3 2 2 3
1 2 3
1 2
2 3
answer: NO
3) WA 38: test
5
3 2 2 2
1 2 3
1 2
2 3
answer: NO |
| WA#6 | yaretsd | 1547. Перебор паролей | 10 июл 2026 01:22 | 7 |
WA#6 yaretsd 12 май 2007 03:36 Re: WA#6 DixonD (Lviv NU) 8 мар 2008 19:26 I got also WA at #6 and made some tests on the input. It seems that the line
if (N == 34 && M == 49) while (1);
got TLE (6) so the test is 34 49.
My answer to this test is
a-niaacgvtxwdouniwkovyjlpaaaerlqkyo
niaacgvtxwdouniwkovyjlpaaaerlqkyp-aaarepihxnlfzhjsqrzpokzcbpyfypjwat
aaarepihxnlfzhjsqrzpokzcbpyfypjwau-aqaaaaaaaaiiovpgvvmsnhsbbrtjgmuqbw
aqaaaaaaaaiiovpgvvmsnhsbbrtjgmuqbx-bejdhnxluhaaainzrkuauccrqbastmtecb
bejdhnxluhaaainzrkuauccrqbastmtecc-bssejrqozpnkflharcuholuvjdvwynyaaa
bssejrqozpnkflharcuholuvjdvwynyaaa-chbflvjseyarrdiqpnyomjekfzqbtgnktz
chbflvjseyarrdiqpnyomjekfzqbtgnkua-cvkgnzcvkgnzcvkgnzcvkgnzcvkgnzcvkm
cvkgnzcvkgnzcvkgnzcvkgnzcvkgnzcvkn-djthqcvyppbgonlwmkhcidxnzrelirsgaz
djthqcvyppbgonlwmkhcidxnzrelirsgba-dycisgpbuxooafnmkvljgbhcwmyqdkhqrm
dycisgpbuxooafnmkvljgbhcwmyqdkhqrn-emljukifaapbxjvblttjroekmwfuxvlxyx
emljukifaapbxjvblttjroekmwfuxvlxyy-faukwobifopcxpqshrtxbwaaaxbkkpmjnr
faukwobifopcxpqshrtxbwaaaxbkkpmjns-fpdlyrulkxckjhsigcydztjvnaayrhdnnv
fpdlyrulkxckjhsigcydztjvnaayrhdnnw-gdmnachtlazghlttujryytfbucbeeqsbil
gdmnachtlazghlttujryytfbucbeeqsbim-grvoczgrvoczgrvoczgrvoczgrvoczgrvv
grvoczgrvoczgrvoczgrvoczgrvoczgrvw-hgepfczvawqgsjxebkkytlmodnpsxrwcmh
hgepfczvawqgsjxebkkytlmodnpsxrwcmi-hunqhgsygfdoebytzvpfriwdajjxsklnct
hunqhgsygfdoebytzvpfriwdajjxsklncu-iiwrjkmblnqvpuajygtmpgfrxfecndaxtf
iiwrjkmblnqvpuajygtmpgfrxfecndaxtg-ixfslofeqwedbmbzwrxtndpguayhhvqijr
ixfslofeqwedbmbzwrxtndpguayhhvqijs-jlotnryhwerknedpvdcalayvqwsmcoftaa
jlotnryhwerknedpvdcalayvqwsmcoftaa-jzxupvrlbnerywfftoghiyiknsmqxgvdqp
jzxupvrlbnerywfftoghiyiknsmqxgvdqq-kogvrzkogvrzkogvrzkogvrzkogvrzkohb
kogvrzkogvrzkogvrzkogvrzkogvrzkohc-lcpwuddrmefgwgilqkovetbohkbamrzyxn
lcpwuddrmefgwgilqkovetbohkbamrzyxo-lqyxwgwurmsohykbovtccqldefvfhkpjnz
lqyxwgwurmsohykbovtccqldefvfhkpjoa-mfhyykpxwvfvtqlrngxjanusbbpkcdeuel
mfhyykpxwvfvtqlrngxjanusbbpkcdeuem-mtraaaaaaadyagcaylnbwefjfiwhlkxzyt
mtraaaaaaadyagcaylnbwefjfiwhlkxzyu-niaaaaaamqmtnchcwhigpdmsazucrszvdb
niaaaaaamqmtnchcwhigpdmsazucrszvdc-nwjcevvhmutscsqniokdufxkroxymgzaaa
nwjcevvhmutscsqniokdufxkroxymgzaaa-oksdgzoksdgzoksdgzoksdgzoksdgzoksh
oksdgzoksdgzoksdgzoksdgzoksdgzoksi-ozbejdhnxluhaabhlcxuvdfatyrziklvtv
ozbejdhnxluhaabhlcxuvdfatyrziklvtw-pnkflharcuholuvjdvwynyaabjmfvzjyxn
pnkflharcuholuvjdvwynyaabjmfvzjyxo-qbtgnktuicuvxmwzchbflvjseyarrdiqpr
qbtgnktuicuvxmwzchbflvjseyarrdiqps-qqchpomxnlidjeypacedivahvrcqaaaaaa
qqchpomxnlidjeypacedivahvrcqaaaaaa-relirsgastvkuxaezdjthqcvyppbgonlwp
relirsgastvkuxaezdjthqcvyppbgonlwq-rsujtvzdycisgpbuxooafnmkvljgbhcwnb
rsujtvzdycisgpbuxooafnmkvljgbhcwnc-shdkvzshdkvzshdkvzshdkvzshdkvzshdn
shdkvzshdkvzshdkvzshdkvzshdkvzshdo-svmlydlkitjhdzfaukwobifopcxpqshrtz
svmlydlkitjhdzfaukwobifopcxpqshrua-tjvnacjothflsugpqhyezmsbiabaabensx
tjvnacjothflsugpqhyezmsbiabaabensy-tyeockxqtkjwbjigrhfbxcysiulzgdmnax
tyeockxqtkjwbjigrhfbxcysiulzgdmnay-umnpeoqtysxdnbjwpsjivaihfqgeawbxrj
umnpeoqtysxdnbjwpsjivaihfqgeawbxrk-vawqgsjxebkkytlmodnpsxrwcmaivorihv
vawqgsjxebkkytlmodnpsxrwcmaivorihw-vpfriwdajjxsklncmorwqvbkzhunqhgsyh
vpfriwdajjxsklncmorwqvbkzhunqhgsyi-wdoskzwdoskzwdoskzwdoskzwdoskzwdot
wdoskzwdoskzwdoskzwdoskzwdoskzwdou-wrxtndpguayhhvqijlabeukemqvwvdoaaa
wrxtndpguayhhvqijlabeukemqvwvdoaaa-xgguphijzjlotnryhwerknedpvdcaaaaud
xgguphijzjlotnryhwerknedpvdcaaaaue-xupvrlbnerywfftoghiyiknsmqxgvdqjmd
xupvrlbnerywfftoghiyiknsmqxgvdqjme-yiywtouqkamdqxveesnfghxhjmrlpwfucp
yiywtouqkamdqxveesnfghxhjmrlpwfucq-yxhxvsntpizlcpwuddrmefgwgilqkovetb
yxhxvsntpizlcpwuddrmefgwgilqkovetc-zlqyxwgwurmsohykbovtccqldefvfhkpjn
zlqyxwgwurmsohykbovtccqldefvfhkpjo-zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz
Can anyone write the correct answer?
Thank you
Edited by author 19.03.2008 18:53 I don't understant what's wrong, here are the number of pieces each processor has:
34 49
27285448088939550474430463423979178157730683277
27285448088939550474430463423979178157730683277
27285448088939550474430463423979178157730683277
27285448088939550474430463423979178157730683277
27285448088939550474430463423979178157730683277
27285448088939550474430463423979178157730683277
27285448088939550474430463423979178157730683277
27285448088939550474430463423979178157730683277
27285448088939550474430463423979178157730683277
27285448088939550474430463423979178157730683277
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
27285448088939550474430463423979178157730683276
(26^34) % M = 10 so I distributed the 10 remaining strings on the first processors, according to the sample test (when the remainder was 2)
Any hint?
solved!
'bssejrqozpnkflharcuholuvjdvwynyaaa' on processor 5 and 6 is obviously wrong Re: WA#6 IgorKoval(from Pskov) 15 мар 2012 23:34 input:
34 49
output:
a-niabcscehmgkraoxkdfwwinvutdtrojpm
niabcscehmgkraoxkdfwwinvutdtrojpn-abrbdglfjpznwjcevvhmutscsqniokdufz
abrbdglfjpznwjcevvhmutscsqniokduga-aqacfkeioymvibduugltsrbrpmhnjctewm
aqacfkeioymvibduugltsrbrpmhnjctewn-bejdhnxluhacttfksrqaqolgmibsdvipmz
bejdhnxluhacttfksrqaqolgmibsdvipna-bssejrqozpnkflharcuholuvjdvwynyadm
bssejrqozpnkflharcuholuvjdvwynyadn-chbflvjseyarrdiqpnyomjekfzqbtgnktz
chbflvjseyarrdiqpnyomjekfzqbtgnkua-cvkgnzcvkgnzcvkgnzcvkgnzcvkgnzcvkm
cvkgnzcvkgnzcvkgnzcvkgnzcvkgnzcvkn-djthqcvyppbgonlwmkhcidxnzrelirsgaz
djthqcvyppbgonlwmkhcidxnzrelirsgba-dycisgpbuxooafnmkvljgbhcwmyqdkhqrm
dycisgpbuxooafnmkvljgbhcwmyqdkhqrn-emljukifagbvlxpcjgpqdyqrtisuycxbhz
emljukifagbvlxpcjgpqdyqrtisuycxbia-faukwobifopcxpqshrtxbwagqemzsvmlyl
faukwobifopcxpqshrtxbwagqemzsvmlym-fpdlyrulkxckjhsigcydztjvnahenobwox
fpdlyrulkxckjhsigcydztjvnahenobwoy-gdmnavnoqfpruztyeockxqtkjwbjigrhfj
gdmnavnoqfpruztyeockxqtkjwbjigrhfk-grvoczgrvoczgrvoczgrvoczgrvoczgrvv
grvoczgrvoczgrvoczgrvoczgrvoczgrvw-hgepfczvawqgsjxebkkytlmodnpsxrwcmh
hgepfczvawqgsjxebkkytlmodnpsxrwcmi-hunqhgsygfdoebytzvpfriwdajjxsklnct
hunqhgsygfdoebytzvpfriwdajjxsklncu-iiwrjkmblnqvpuajygtmpgfrxfecndaxtf
iiwrjkmblnqvpuajygtmpgfrxfecndaxtg-ixfslofeqwedbmbzwrxtndpguayhhvqijr
ixfslofeqwedbmbzwrxtndpguayhhvqijs-jlotnryhwerknedpvdcalayvqwsmcoftad
jlotnryhwerknedpvdcalayvqwsmcoftae-jzxupvrlbnerywfftoghiyiknsmqxgvdqp
jzxupvrlbnerywfftoghiyiknsmqxgvdqq-kogvrzkogvrzkogvrzkogvrzkogvrzkohb
kogvrzkogvrzkogvrzkogvrzkogvrzkohc-lcpwuddrmefgwgilqkovetbohkbamrzyxn
lcpwuddrmefgwgilqkovetbohkbamrzyxo-lqyxwgwurmsohykbovtccqldefvfhkpjnz
lqyxwgwurmsohykbovtccqldefvfhkpjoa-mfhyykpxwvfvtqlrngxjanusbbpkcdeuel
mfhyykpxwvfvtqlrngxjanusbbpkcdeuem-mtraaojbcdtdfinhlsbpylegxxjowvueux
mtraaojbcdtdfinhlsbpylegxxjowvueuy-niabcscehmgkraoxkdfwwinvutdtrojplj
niabcscehmgkraoxkdfwwinvutdtrojplk-nwjcevvhmutscsqniokdufxkroxymgzabv
nwjcevvhmutscsqniokdufxkroxymgzabw-oksdgzoksdgzoksdgzoksdgzoksdgzoksh
oksdgzoksdgzoksdgzoksdgzoksdgzoksi-ozbejdhnxluhacttfksrqaqolgmibsdvit
ozbejdhnxluhacttfksrqaqolgmibsdviu-pnkflharcuholuvjdvwynyadicgmwktfzf
pnkflharcuholuvjdvwynyadicgmwktfzg-qbtgnktuicuvxmwzchbflvjseyarrdiqpr
qbtgnktuicuvxmwzchbflvjseyarrdiqps-qqchpomxnlidjeypasfmjsthbtuwlvybgd
qqchpomxnlidjeypasfmjsthbtuwlvybge-relirsgastvkuxaezdjthqcvyppbgonlwp
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xgguphijzjlotnryhwerknedpvdcalayvs-xupvrlbnerywfftoghiyiknsmqxgvdqjmd
xupvrlbnerywfftoghiyiknsmqxgvdqjme-yiywtouqkamdqxveesnfghxhjmrlpwfucp
yiywtouqkamdqxveesnfghxhjmrlpwfucq-yxhxvsntpizlcpwuddrmefgwgilqkovetb
yxhxvsntpizlcpwuddrmefgwgilqkovetc-zlqyxwgwurmsohykbovtccqldefvfhkpjn
zlqyxwgwurmsohykbovtccqldefvfhkpjo-zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz Thanks for the test :) I solved it using base-26 long arithmetics, but forgot to prepend leading zeroes (leading 'a'), so could output "brg" instead of "aabrg" |
| Possible way to solve it (long arithmetic ) | Mahilewets | 1547. Перебор паролей | 10 июл 2026 01:06 | 2 |
Calculate powers of 26 and prefix sums of powers of 26.
Calculate ranges by integer division.
Calculate each password from left to right like you would calculate k-permutation using factorial digit system. Base-26 arithmetics simplifies things a lot here :) |
| What if pawns eats bishop? | Denis Koshman | 1398. Слон и пешка | 9 июл 2026 23:39 | 3 |
It's not clear if black player can continue movement or not after eating white bishop. Bishop moves first, so if at first pawn can capture bishop it does not matter. On the next moves bishop can avoid such positions where pawn can capture it. Just according to problem statement it's white wins :), so looks weird |
| ADMIN! | coder | 2137. Динамическая сложность строки | 9 июл 2026 22:45 | 1 |
Please, check 142 test, C++ fread failed for this test case. scanf accepted.
After fread I can try trim space symbols (ASCII code <= 32) from start and end, any more WA142. |
| Any hint? | Alexandru Farcasanu | 1915. Руины титанов: воссоздание былого | 9 июл 2026 22:39 | 6 |
Any hint? Alexandru Farcasanu 20 окт 2012 23:26 Any hint for solving this problem? number of possible operations is only 1m > number of possible operations is only 1m
Hah! Somehow reading this here (even though it's clear in the problem statement) made me see the way...thanks. memcpy (for c++) and million.., and not any more ;p |
| How solve it O(N) ? | coder | 2137. Динамическая сложность строки | 9 июл 2026 22:09 | 1 |
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